Answer:
21.22s
Explanation:
initial velocity u=87m/s
acceleration a=-4.10 m/s²
velocity v=0
time t=?
From Newton's first law of motion
V=u+at
0=87-4.10t
-87=-4.1t
t= -87/-4.1
t= 21.22 s
Answer:
its a
Explanation:
scrape - push or pull a hard or sharp implement across (a surface or object) so as to remove dirt or other matter.
(150 km/hr) x (1000 m/km) x (hr/3600sec) = 41-2/3 m/sec
Acceleration = (change in speed) / (time for the change)
Change in speed = (41-2/3 minus 0) = 41-2/3 m/s
Time for the change = 0.5sec.
Acceleration = (41-2/3 m/s) / (0.5 sec) = 83-1/3 m/s² .
Acceleration of gravity = 9.8 m/s² .
Acceleration of sneezed air = (83-1/3) / (9.8) = <em>8.5 g </em>(rounded)
Answer:
The formula for the separation between the plates, d = V/E and d = 1.02 mm
Explanation:
Here is the complete question
The electric field strength between the plates of a simple air Capacitor is equal to the voltage across the plates divided by the distance between them When a voltage of 112. V is put across the plates of such a capacitor an electric field strength of 1.1 kV/cm is measured. Write an equation that will let you calculate the distance d between the plates. Your equation should contain only symbols. Be sure you define each symbol
Solution
The electric field strength between the plates of a simple air capacitor is given by E = V/d where V = electric potential between the plates and d = separation between the plates.
Making d the separation between the plates subject of the formula, we have
d = V/E
Since V = 112 V and E = 1.1 kV/cm = 1100 V/cm
Substituting the values of the variables into the equation, we have
d = V/E
d = 112 V/1100 V/cm
d = 0.102 cm
d = 1.02 mm
So, the formula for the separation between the plates, d = V/E and d = 1.02 mm.
