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Anna35 [415]
3 years ago
10

Help. Please.

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
7 0
The way you can solve this, is by using this equation to solve for percent acidity:

%acidity = (grams of acetic acid / grams of vinegar) * 100.

Hope this helps!
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Compute the following and give your answer on scientific notation
Nata [24]

Answer:

6*10^-3

Hope it helps

Procedure in the attached file

4 0
3 years ago
What mass in grams of nitric acid is required to react with 750 g C7H8?
lara31 [8.8K]

Answer:

932.27 i think

Explanation:

5 0
4 years ago
How many moles are in 1.5 x 10^20 molecules of NH3?
Keith_Richards [23]
<span>Because the question is asking moles of NH3, the compound, any subscripts are irrelevant. It only wants to know how many moles of NH3 molecules, not individual atoms.

Therefore, we can simply convert to moles. 1.5x10^23/6.022x10^23 = .249 moles of NH3.

(If it were to ask moles of Hydrogen, for example, you would multiply the answer by 3, because there are 3 atoms of Hydrogen per one molecule of NH3. But this only asks for moles of the entire compound).  

hope you have a great day! :)
</span>
5 0
4 years ago
3. What is the density of a 100 grams (g) box that displaces 20 mL of water?
Zolol [24]

Answer: the density is 997 kg

Explanation:

8 0
3 years ago
A gas balloon has a volume of 80.0 mL at 300K, and a pressure of 50.0 kPa. If the pressure changes to 80 kPa and the temperature
fomenos

Answer:  The new volume is 53.3 ml

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas =  50.0 kPa

P_2 = final pressure of gas = 80.0 kPa

V_1 = initial volume of gas = 80.0 ml

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 300K

T_2 = final temperature of gas = 320K

Now put all the given values in the above equation, we get:

\frac{50.0\times 80.0}{300}=\frac{80.0\times V_2}{320}

V_2=53.3ml

The new volume is 53.3 ml

4 0
3 years ago
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