What should be added to 61.01 to get the smallest three-digit number?
1 answer:
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See the attached figure which represent the rest of the question.
The rest of the question is the attached figure.
==============================================
As shown in the attached figure:
(1) ΔMNL is a right triangle at ∠MNL and ∠NML = 58°
∴ ∠L = 180° - (90°+58°) = 32°
(2) ΔQNL is a right triangle at ∠QNL and ∠QLN = 32°
∴ ∠Q = 180° - (90°+32°) = 58°
So, for both of ΔMNL and ΔQNL
1. ∠NLM = ∠ NLQ = 32°
2. ∠Q = ∠M = 58°
3. side NL = side NL
∴ ΔMNL is congruent to ΔQNL by AAS
=======OR=======
So, for both of ΔMNL and ΔQNL
1. ∠MNL = ∠QNL = 90°
2. side NL = side NL
3. ∠NLM = ∠ NLQ = 32°
∴ ΔMNL is congruent to ΔQNL by ASA
=====================================
So, the correct answer is the first option
Yes, they are congruent by either ASA or AAS
The rest of the question is the attached figure.
==============================================
As shown in the attached figure:
(1) ΔMNL is a right triangle at ∠MNL and ∠NML = 58°
∴ ∠L = 180° - (90°+58°) = 32°
(2) ΔQNL is a right triangle at ∠QNL and ∠QLN = 32°
∴ ∠Q = 180° - (90°+32°) = 58°
So, for both of ΔMNL and ΔQNL
1. ∠NLM = ∠ NLQ = 32°
2. ∠Q = ∠M = 58°
3. side NL = side NL
∴ ΔMNL is congruent to ΔQNL by AAS
=======OR=======
So, for both of ΔMNL and ΔQNL
1. ∠MNL = ∠QNL = 90°
2. side NL = side NL
3. ∠NLM = ∠ NLQ = 32°
∴ ΔMNL is congruent to ΔQNL by ASA
=====================================
So, the correct answer is the first option
Yes, they are congruent by either ASA or AAS