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vesna_86 [32]
4 years ago
8

4.

Physics
2 answers:
aleksandrvk [35]4 years ago
7 0

ribosomes

an animal cell with a nucleus

animal

givi [52]4 years ago
5 0

Answer:

4) Chloroplasts, 5) An animal cell with a nucleus, 6) many-celled organisms.

Explanation:

4) Chloroplasts are organelles present in eukariotic cells that produce food with the help of sunlight via photosynthesis.

5) Every cell has a nucleus. Bacteriae are prokariotic cells, while vegetal and animal cells are eukariotic cells, in which cytoplasm is exclusive for organells. Hence, the right answer is: An animal cell with a nucleus.

6) Specialized cells are cells that help in functioning of many-celled organisms. Therefore, the right choice is: many-celled organisms.

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A horizontal uniform 1.20-N meter stick is held up by two vertical strings, one at the 20-cm mark and the other at the 60-cm mar
harina [27]

The tension in the string at the 60-cm mark will be 0.9 N.The tension force is applied along the whole length of the wire, pulling energy equally on both ends.

<h3>What is tension force?</h3>

The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.

The given data in the problem is;

The length of  the stick is, L= 1.20 m =120 cm

T is the tension in the string at the 60-cm mark;

T₁ is the tension at the 20-cm mark

From the torque equilibrium law;

\rm mg(30)-T_2(40)+T_2 (40) =0 \\\\\ T_1(0)=mg (30)\\\\\ T_2(40)=1.2 (30) \\\\ T_2= 0.9 \ N

Hence the tension in the string at the 60-cm mark will be 0.9 N.

To learn more about the tension force refer to the link;

brainly.com/question/2287912

#SPJ3

5 0
3 years ago
A sled starts at rest with 51,450 J of potential energy. After traveling part of the way down the slope, the sled has 32,781 J o
Ugo [173]
Because of conservation of energy, ep is equal to ek.
at that point ep=ek
the kinetic energy would be 32,781J

8 0
3 years ago
Suppose a free-fall ride at an amusement park starts at rest and is in free fall. What is the velocity of the ride after 2.3 s?
horsena [70]

Answer:

V = a * t = 9.8 m/s^2 * 2.3 s = 22.5 m/s   velocity after 2.3 s

S = 1/2 g t^2      since initial speed is zero

S = 1/2 * 9.8 m/s^2 * 5.29 s^2 = 25.9 m

8 0
3 years ago
A pure substance has a/an
Evgesh-ka [11]

Answer:

Element or a compound.

Explanation:

6 0
4 years ago
Tired of being chased by a jaguar, you set a trap. Hoping to drop it on the jaguar, you try to push a
Alenkasestr [34]

Answer: acceleration = 3.27m/s^2

Explanation:

Given that the

Mass M = 44kg

Angle Ø = 15 degree

Coefficient of friction ų = 0.7

Force F = 222N

F - Fr = ma ...... (1)

Where Fr = frictional force

Fr = ųN

N = normal reaction = mg

Fr = ųmgsinØ

Fr = 0.7 × 44 × 9.81 × sin 15

Fr = 78.2N

Substitutes Fr, F and M into equation one.

222 - 78.2 = 44a

143.79 = 44a

Make a the subject of formula

a = 143.79/44

Acceleration a = 3.27 m/s^2

6 0
4 years ago
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