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3 years ago

4.

Physics

2 answers:

aleksandrvk [35]3 years ago

7 0

ribosomes

an animal cell with a nucleus

animal

givi [52]3 years ago

5 0

Answer:

4) Chloroplasts, 5) An animal cell with a nucleus, 6) many-celled organisms.

Explanation:

4) Chloroplasts are organelles present in eukariotic cells that produce food with the help of sunlight via photosynthesis.

5) Every cell has a nucleus. Bacteriae are prokariotic cells, while vegetal and animal cells are eukariotic cells, in which cytoplasm is exclusive for organells. Hence, the right answer is: An animal cell with a nucleus.

6) Specialized cells are cells that help in functioning of many-celled organisms. Therefore, the right choice is: many-celled organisms.

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PLEASE HELP ME!!!!!!!

melamori03 [73]

This it you can do it boy or girl 

6 0

3 years ago

The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou

puteri [66]

Answer:

$t=5.3687\ s$ is the time taken by the car to accelerate the desired range of the speed from zero at full power.

Explanation:

Given:

Range of speed during which constant power is supplied to the wheels by the car is $0\ mph\ to\ 70\ mph$ .

Initial velocity of the car, $v_i=0\ mph$

final velocity of the car during the test, $v_f=32\ mph=14.3052\ m.s^{-1}$

Time taken to accelerate form zero to 32 mph at full power, $t=1.2\ s$

initial velocity of the car, $u_i=0\ mph$

final desired velocity of the car, $u_f=64\ mph=28.6105\ m.s^{-1}$

Now the acceleration of the car:

$a=\frac{v_f-v_i}{t}$

$a=\frac{14.3052-0}{1.2}$

$a=11.921\ m.s^{-1}$

Now using the equation of motion:

$u_f=u_i+a.t$

$64=0+11.921\times t$

$t=5.3687\ s$ is the time taken by the car to accelerate the desired range of the speed from zero at full power.

8 0

2 years ago

Find the distance in nm between two slits that produces the first minimum for 410-nm violet light at an angle of 14.5°.

Galina-37 [17]

Answer:

820 nm

Explanation:

We are given that

Wavelength= $\lambda=410 nm$

$\lambda=410\times 10^{-9} m$

$1nm=10^{-9} m$

$\theta=14.5^{\circ}$

For first minimum therefore

m=0

We know that for destructive interference

$(m+\frac{1}{2})\lambda=dsin\theta$

Substitute the values

$(0+\frac{1}{2})\times 410\times 10^{-9}=dsin 14.5$

$d=\frac{410\times 10^{-9}}{2\times sin 14.5}$

$d=820\times 10^{-9} m=820 nm$

Hence, the distance between two slits that produces the first minimum=820 nm

5 0

2 years ago

Read 2 more answers

Which sentence is correct?

Alexeev081 [22]

Answer:

pretty sure its B if it isnt im so so sorry

Explanation:

7 0

2 years ago

If 128 v is required to push 4.00 A of current though a resistor, what is the resistance

prisoha [69]

Answer:

32.0 Ω

Explanation:

Ohm's law:

V = IR

128 V = (4.00 A) R

R = 32.0 Ω

8 0

2 years ago