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3 years ago

8

Rings of dust and icy particles are found around which planets? a. all planets which have moons associated with them b. only Sat

urn c. all for terrestrial planets d. all four jovian planets.

1 answer:

lisov135 [29]3 years ago

5 0

Answer:

d. all four jovian planets.

Explanation:

The Jovian planets are as follows -

URANUS , SATURN , JUPITER, and NEPTUNE .

All these four jovian planets are having the rings , and the rings are made up of infinite number of small pieces of the ice and the rock .

Hence ,

These planets are comparatively small and dense cores surrounded by massive layers of gas .

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The temperature decreases 5°C in one hour and then decreases another 3°C in the next hour. Does this fit the definition of weath

Rus_ich [418]

Answer:

what is your age po? what

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3 years ago

If a ball has a velocity of 18 m/s, how far does it travel in 15 seconds

Stolb23 [73]

Answer:

The answer is

<h2>270 m</h2>

Explanation:

To find the distance when given the velocity and time we use the formula

<h3>distance = velocity × time</h3>

From the question

velocity of the ball = 18 m/s

time = 15 s

So the distance is

distance = 18 × 15

We have the final answer as

<h3>270 m</h3>

Hope this helps you

7 0

3 years ago

A hockey player applies an average force of 80.0 N to a

denpristay [2]

Answer:

$Impulse = 8.0Ns$

Explanation:

Given

$Force = 80.0N$

$Mass = 0.25kg$

$Time = 0.10s$

Required

Determine the impulse

The impulse is calculated as follows:

$Impulse = Force * Time$

Substitute values for Force and Time

$Impulse = 80.0N * 0.10s$

$Impulse = 8.0Ns$

<em>Hence, the impulse experienced is 8.0Ns</em>

5 0

3 years ago

1. Bone has a Young’s modulus of about

Blababa [14]

#1

As we know that

$Y = \frac{stress}{strain}$

now plug in all data into this

$1.8\times 10^{10} = \frac{1.68 \times 10^8}{strain}$

$strain = 9.33 \times 10^{-3}$

now from the formula of strain

$strain = \frac{\Delta L}{L}$

$9.33 \times 10^{-3} = \frac{\Delta L}{0.54}$

$\Delta L = 5.04 \times 10^{-3} m$

$\Delta L = 5.04 mm$

#2

As we know that

pressure * area = Force

here we know that

$Area = 3.53 \times 11.6 = 40.95 m^2$

$P = 0.2 atm = 0.2 \times 1.01 \times 10^5 = 2.02\times 10^4 Pa$

now force is given as

$F = 40.95 \times (2.02\times 10^4) = 8.27 \times 10^5 N$

#3

As we know that density of water will vary with the height as given below

$\rho = \frac{\rho_0}{1 - \frac{\Delta P}{B}}$

here we know that

$\Delta P = 2600 atm = 2600 \times 1.01 \times 10^5 = 2.63\times 10^8 Pa$

$B = 2.3 \times 10^9 N/m^2$

now density is given as

$\rho = \frac{1050}{1 - \frac{2.63\times 10^8}{2.3 \times 10^9}}$

$\rho = 1185.3 kg/m^3$

#4

as we know that pressure changes with depth as per following equation

$P = P_o + \rho g h$

here we know that

$P = 3 P_0$

now we will have

$3P_0 = P_0 + \rho g h$

$2P_0 = \rho g h$

$2(1.01 \times 10^5) = 1025 (9.81)(h)$

here we will have

$h = 20.1 m$

so it is 20.1 m below the surface

#5

Here net buoyancy force due to water and oil will balance the weight of the block

so here we will have

$mg = \rho_1V_1g + \rho_2V_2g$

$A(0.0476)979 = 922(A)(0.0476 - x) + 1000(A)(x)$

$46.6 = 43.89 - 922x + 1000x$

$x = 3.48 cm$

so it is 3.48 cm below the interface

5 0

4 years ago

Positively-charged particles consisting of two protons and two neutrons emitted by radioactive materials are

BARSIC [14]

Answer:

The answer to your question is Alpha particles.

Explanation: An electron released by a radioactive nucleus that causes a neutron to change into a proton is called a beta particle.

6 0

3 years ago