Answer:
<em>The second particle will move through the field with a radius greater that the radius of the first particle</em>
Explanation:
For a charged particle, the force on the particle is given as
also recall that work is force times the distance traveled
work = F x d
so, the work on the particle = F x d,
where the distance traveled by the particle in one revolution = 
Work on a particle = 2πrF = 
This work is proportional to the energy of the particle.
And the work is also proportional to the radius of travel of the particles.
Since the second particle has a bigger speed v, when compared to the speed of the first particle, then, the the second particle has more energy, and thus will move through the field with a radius greater that the radius of the first particle.
Answer:
a) 31.4 m/s
b) 50.2 m
Explanation:
a) When an object is free falling, its speed is determined by the gravity force giving it acceleration. Equation for the velocity of free fall started from the rest is:
v = g • t
g - is gravitational acceleration which is 9.81 m/s^2, sometimes rounded to 10
t - is the time of free fall
So:
v = 9.81 m/s^2 • 3.2
v = 31.4 m/s ( if g is rounded to 10, then the velocity is 10 • 3.2 = 32 m/s)
b) To determine the distance crossed in free fall we use the equation:
s = v0 + gt^2/2
v0 - is the starting velocity (since object started fall from rest, its v0 is 0)
s = gt^2/2
s = 9.81 m/s^2 • 3.2^2 / 2
s = 50.2 m (if we round g to 10 then the distance is 10 • 3.2^2/2 = 51.2 meters)
Answer:
the answers the correct one is d
Explanation:
The speed of sound is constant so we can use the relations of uniform motion
v = x / t
x = v t
now let's calculate the distance for each person
t = 5s
x₁ = 300 5
x₁ = 1500 m
t = 6s
x₂ = 300 6
x₂ = 1800 m
therefore we have two possibilities
a) the two people are on the same side, therefore the distance between them is
Δx = x₂- x₁
Δx = 1800 - 1500
Δx = 300 m
let's reduce to km
Δx = 0.300 km
b) people are on opposite sides of the sound
Δx = x₂ + x₁
Δx = 1800 + 1500
Δx = 3300 m
Δx = 3.3 km
when checking the answers the correct one is d
Answer:
ω=v/r.
Explanation:
<em><u>angular velocity= linear velocity/radius</u></em>
Answer:
The magnitude of the lift force L = 92.12 kN
The required angle is ≅ 16.35°
Explanation:
From the given information:
mass of the airplane = 9010 kg
radius of the airplane R = 9.77 mi
period T = 0.129 hours = (0.129 × 3600) secs
= 464.4 secs
The angular speed can be determined by using the expression:
ω = 2π / T
ω = 2 π/ 464.4
ω = 0.01353 rad/sec
The direction 
θ = 16.35°
The magnitude of the lift force L = mg ÷ Cos(θ)
L = (9010 × 9.81) ÷ Cos(16.35)
L = 88388.1 ÷ 0.9596
L = 92109.32 N
L = 92.12 kN
