Answer:
I believe the answer is A.
Explanation:
This section states that protozoa live in all bodies of water therefore B can not be an answer because it says protozoa dose not live in any body of water.
I hope this answers your question.
Answer:
44.2 mmHg
Explanation:
We have to apply the colligative property of lowering vapor pressure:
P° - P' = P° . Xm
where P' refers to vapor pressure of solution
P° refers to vapor pressure of pure solvent
Xm is the mole fraction of solute
Let's determine the mole fraction (moles of solute / Total moles)
Total moles = Moles of solute + Moles of solvent
Moles of solute → 15 g . 1 mol/18g = 0.833 moles
Moles of solvent → 100 g . 1mol / 46 g = 2.174 moles
Total moles = 0.833 + 2.174 = 3.007
Xm = 0.833 / 3.007 = 0.277
We replace data in the formula: 61.2 mmHg - P' = 61.2 mmHg . 0.277
P' = - (61.2 mmHg . 0.277 - 61.2 mmHg) → 44.2 mmHg
the answer is A convalent
To convert a number without the use of the expression 10^-4 you would have to treat it like an integer line for instance on an integer line the negative is to the left and the positive number is to the right so 3.91*10^-4 means that the decimal would have to move 4 places to the left so the answer would be .000391 instead of 3.91*10^-4.
I hope this helps you :)
Answer:
6.25×10⁻⁶ g / cm³
Explanation:
Density is the relation between mass and volume as this formula shows.
Density of a compound = Mass of the compound / Volume of compound
In the values, we were given:
0.0124 kg / 1983 mm³ = 6.25×10⁻⁶ kg/mm³
This number means that in a volume of 1 mm³ of compound, the mass of it occupies 6.25×10⁻⁶ kg. Let's make a rule of three:
1 cm³ = 1×10⁻³ mm³
In 1 mm³ we have 6.25×10⁻⁶ kg of compound
So in 1×10⁻³ mm³ we would have (1×10⁻³ mm³ . 6.25×10⁻⁶ kg) / 1 mm³ =
6.25×10⁻⁹ kg
Now let's convert the kg to g.
1 kg = 1000 g
6.25×10⁻⁹ kg . 1000 = 6.25×10⁻⁶ g
Finally density is : 6.25×10⁻⁶ g / cm³
