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3 years ago

I really really need your help!!

Mathematics

2 answers:

marissa [1.9K]3 years ago

4 0

Answer:

1.) 1/2x = 32

2.) 3x = 18

3.) x/7 = 4

4.) 5m=105

divide both sides by 5

m= 21

5.) -2c=-32

divide both sides by -2

c=16

6.) x/4=-44

multiply both sides by 4

x=-176

7.) s/-3 = -21

multiply both sides by -3

s=63

mr Goodwill [35]3 years ago

4 0

1. 16
2. 6
3. 28
4. M=21
5. C=16
6. X=-176
7. S=63

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The population of a school is 800 students and is increasing at a rate of 4% per year; 5 year

Darya [45]

Answer:

960 i think

Step-by-step explanation:

800 x 0.04 = 32

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800 + 160 = 960

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3 years ago

Which expression is equivalent to sqrt8x^7y^8? assume x>0

Ilia_Sergeevich [38]

Answer:

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Step-by-step explanation:

Given

$\sqrt{8x^7y^8$

Required

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$\sqrt{8x^7y^8$

Separate each factor with multiplication sign

$\sqrt{8*x^7*y^8$

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$\sqrt{4 * 2 *x^6 * x*y^8$

Split each factor

$\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Evaluate $\sqrt4$

$2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Apply law of indices:

$2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}$

$2 * \sqrt{2} * x^3 * \sqrt{x} * y^4$

Reorder

$2* x^3 * y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2*x}$

$2x^3y^4 * \sqrt{2x}$

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$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

8 0

3 years ago

Read 2 more answers

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denpristay [2]

Answer:

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Step-by-step explanation:

We want to solve the linear equation -3w-4=w+3

We group like terms to get

$- 3w - w = 3 + 4$

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$w = - \frac{7}{4}$

Now let us check

$- 3 \times - \frac{7}{4} - 4 = - \frac{7}{4} + 3$

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$\frac{5}{4} = \frac{5}{4}$

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3 years ago

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3 years ago

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Answer:

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4 years ago