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laila [671]
2 years ago
13

1.10) For a fixed mass of gas at constant temperature, if the volume of the gas (V) increases to twice its original amount, the

pressure of the gas (P) will be
A)2P
В )1/2 Р
C)P
D)4P​
Physics
2 answers:
Aliun [14]2 years ago
7 0
B. 1/2p
From the relation
P1V1=P2V2
P2=P1V1/V2
If everything equals one
P2=1*1/2(1)
That would equal 1/2
I hope this helps
Please mark as brainliest
kow [346]2 years ago
7 0

Answer:

B

Explanation:

<em>According</em><em> </em><em>to </em><em>boyle's </em><em>law</em><em> </em><em>for </em><em>a </em><em>gas </em><em>the </em><em>pressure</em><em> </em><em>and </em><em>volume</em><em> </em><em>are </em><em>inversely</em><em> proportional</em><em>.</em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>simply </em><em>means </em><em>when </em><em>one </em><em>increases</em><em> the</em><em> </em><em>other </em><em>one</em><em> </em><em>reduces </em><em>and </em><em>when </em><em>the </em><em>other </em><em>one </em><em>reduces </em><em>the </em><em>other </em><em>increases</em><em>.</em><em>s</em><em>o</em><em> </em><em>in </em><em>this </em><em>case </em><em>the </em><em>volume</em><em> </em><em>increased </em><em>to </em><em>twice </em><em>it </em><em>original </em><em>amount</em><em> </em><em>meaning</em><em> </em><em>the </em><em>pressure</em><em> </em><em>will </em><em>reduce</em><em> </em><em>to </em><em>half </em><em>the </em><em>volume</em><em>.</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

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2 years ago
A shell is fired at an angle of 35° above the horizontal at a velocity of 40 m/s. (a) What is it's speed at the highest point of
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Answer:

Part a)

v_f = v_x = 32.77 m/s

Part b)

T = 4.68 s

Explanation:

Part a)

Shell is fired at speed of 40 m/s at angle of 35 degree

so here we have

v_x = 40 cos35 = 32.77 m/s

v_y = 40 sin35 = 22.94 m/s

since gravity act opposite to vertical speed of the shell so at the highest point of its trajectory the vertical component of the speed will become zero

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Part b)

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so we have

\Delta y = 0

0 = v_y t - \frac{1}{2}gt^2

T = \frac{2v_y}{g}

T = \frac{2(22.94)}{9.81} = 4.68 s

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Answer:

The distance is D  =  2.6 \ m

Explanation:

From the question we are told that

    The wavelength of the light is  \lambda  =  476.1 \ nm  =  476.1 *10^{-9} \ m

      The  distance between the slit is  d =  0.29 \  mm  =  0.29 *10^{-3} \ m

       The  between the first and second dark fringes is  y =  4.2 \ mm  =  4.2 *10^{-3} \ m

Generally  fringe width is mathematically represented as

       y  =  \frac{\lambda * D }{d}

Where D is the distance of the slit to the screen

   Hence

        D  =  \frac{y *  d}{\lambda }

substituting values

       D  =  \frac{ 4.2 *10^{-3} *   0.29 *10^{-3}}{ 476.1 *10^{-9} }

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