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Romashka-Z-Leto [24]
3 years ago
8

Determine if each phrase describes speed or velocity Sort each tile into the appropriate column

Physics
1 answer:
Andreyy893 years ago
4 0

Answer:

Speed

• distance per time

• a scalar quantity

• 400 km/h

Velocity

• a vector quantity

• 20 m/s south

• displacement per time

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In nonequilibrium, total counterclockwise moments = total clockwise moments. *True False
Likurg_2 [28]

Answer:

{ \bf{false}}

Explanation:

Because it breaks the <u>l</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>m</u><u>o</u><u>m</u><u>e</u><u>n</u><u>t</u><u>s</u><u>.</u>

8 0
3 years ago
A car traveling along the highway needs a certain amount of force exerted on it to stop it in a certain distance. More stopping
Lelu [443]

More stopping force is required when the car has to stop in a shorter distance.

<h3>What is the relationship between force and acceleration?</h3>

Force is directly proportional to acceleration according to Newton's second law of motion.

This means that acceleration increases when force increases.

Stopping of a moving car is negative acceleration.

Therefore, more stopping force is required when the car has to stop in a shorter distance.

Learn more about force and acceleration at: brainly.com/question/14343220

#SPJ1

7 0
2 years ago
Solution A has a specific heat of 2.0 J/g◦C. Solution B has a specific heat of 3.8 J/g◦C. If equal masses of both solutions start
fgiga [73]

Answer: 2. Solution A attains a higher temperature.

Explanation: Specific heat simply means, that amount of heat which is when supplied to a unit mass of a substance will raise its temperature by 1°C.

In the given situation we have equal masses of two solutions A & B, out of which A has lower specific heat which means that a unit mass of solution A requires lesser energy to raise its temperature by 1°C than the solution B.

Since, the masses of both the solutions are same and equal heat is supplied to both, the proportional condition will follow.

<em>We have a formula for such condition,</em>

Q=m.c.\Delta T.....................................(1)

where:

  • \Delta T= temperature difference
  • Q= heat energy
  • m= mass of the body
  • c= specific heat of the body

<u>Proving mathematically:</u>

<em>According to the given conditions</em>

  • we have equal masses of two solutions A & B, i.e. m_A=m_B
  • equal heat is supplied to both the solutions, i.e. Q_A=Q_B
  • specific heat of solution A, c_{A}=2.0 J.g^{-1} .\degree C^{-1}
  • specific heat of solution B, c_{B}=3.8 J.g^{-1} .\degree C^{-1}
  • \Delta T_A & \Delta T_B are the change in temperatures of the respective solutions.

Now, putting the above values

Q_A=Q_B

m_A.c_A. \Delta T_A=m_B.c_B . \Delta T_B\\\\2.0\times \Delta T_A=3.8 \times \Delta T_B\\\\ \Delta T_A=\frac{3.8}{2.0}\times \Delta T_B\\\\\\\frac{\Delta T_{A}}{\Delta T_{B}} = \frac{3.8}{2.0}>1

Which proves that solution A attains a higher temperature than solution B.

7 0
3 years ago
Which are ways to improve the design of this experiment? Check all that apply.
Arte-miy333 [17]

Answer:

* Experiment with a higher range of materials

* Use a galvanometer.

* Vary in number of coils of the electromagnet

Explanation:

This is an experiment of electricity and magnetism, in general the best way to improve the results are:

* Experiment with a higher range of materials

   allowing to know the scope of the initial assumptions

* Use a galvanometer.

  The more accurate the readings the error of the derived quantities is the less which will improve the precision of the experiment.

* Vary in number of coils of the electromagnet

  Since it allows to have greater magnetic fields and therefore expand the range of measurements

3 0
3 years ago
Read 2 more answers
A small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of
uysha [10]

Answer:

q = 4.04×10^-12C

n = 2.53×10^7

Explanation:

1. Electrostatic force on charge due to electrical field E is F = qE

Gravitational force due to weight of drop of mass M is F = mg, when net force is zero we have to find the charges on the drop.

2. Charge on drop: since gravitational force is acting downward, electric field is acting upward and we equate both equations.

Therefore, Fg = Fe

qe = mg

q = mg/E

q = 3.50×10^-9kg×9.8m/s²/8480N/c

q = 4.04 × 10^-12

3. Number of protons by quantitization law

n = q/e

n = 4.04× 10^-12/8480

n = 2.53× 10^7

8 0
3 years ago
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