Question

A circle is centered at C(0,0). The point M(0,38) is on the circle.

Answer 1

If the point M(0,38) is on the circle then its radio is:

$r = \sqrt{ 0 ^2+38 ^2} = 38$

Compute the distance between the center and N:

$d = \sqrt{(-5)^2 + (-3)^2} = \sqrt{25+9} = \sqrt{34} \approx 5.83$

Because d < r then point N is INSIDE THE CIRCLE.