D. 1/4 + 1/5 = 5/20 + 4/20 = 9/20 = 45/100 = 0.45
Answer:
5 hours
Step-by-step explanation:
Lillian is deciding between two parking garages.
Let the time required to park be represented by t
A = Amount
From Garage A
A = the amount Garage A would charge if Lillian parks for t hours
B = the amount Garage B would charge if Lillian parks for t hours.
Garage A
Garage A charges an initial fee of $4 to park plus $3 per hour.
A = $4 + $3 × t
A = 4 + 3t
Garage B charges an initial fee of $9 to park plus $2 per hour.
B = $9 + $2 × t
B = 9 + 2t
The hours parked, t, that would make the cost of each garage the same is calculated by equating A to B
A = B
4 + 3t = 9 + 2t
Collect like terms
3t - 2t = 9 - 4
t = 5 hours
Therefore, the hours parked, t, that would make the cost of each garage the same is 5 hours
<span>g(r) = -1 − 7r
g(6)
= -1 - 7*6 = -1 - 42 = -43
Hope it helps!
</span>
Answer:
A) Median: 7
Mode: 8
Range: 5
B) Tyler is wrong, the greater the MAD value, the greater the variability
Step-by-step explanation:
A) Given the data set: 4,6,6,7,7,8,8,8,9
The median is 7 (the middle point in the ordered list)
The mode is 8 (the most repeated number)
The range is 5 (the difference between the highest and lowest values)
