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2 years ago

9

A hypothesis test is conducted with a significance level of 5%. The alternative hypothesis states that more than 65% of a popula

tion

1 answer:

mr_godi [17]2 years ago

8 0

Answer:

Not sure thats the whole question.

Step-by-step explanation:

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For each 70 mm of coloured fabric Alex uses to make his curtains, he also uses 20 cm of white fabric. Express the amount of whit

Fed [463]

Answer:

20×10=200mm

70:200

70/10=7

200/10=20

7:20 is your answer in it's simplest form

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2 years ago

20 points, pls help, its angles

Zina [86]

Okay what’s the question

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2 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by <em>b</em> :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since <em>a/b</em> < <em>c/d</em>, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by <em>b/d</em> to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) < <em>c/d</em>.

For the other side, you can do something similar and divide through everything by <em>d</em> :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and <em>a/b</em> < <em>c/d</em> tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) > <em>a/b</em>.

Then together we get the desired inequality.

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2 years ago

Kbhhkb,hbj,bhjbj,bj,bh

trasher [3.6K]

Answer:

ahahhajajsiajaklaoaoa

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2 years ago

Sylvie is going on vacation. She has already driven 58 miles in one hour. If she then travels for 6 hours at an average speed of

Vlada [557]

The answer would be 360 miles

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2 years ago