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mixas84 [53]
3 years ago
5

Circle the expression that is four times bigger than n N+4. 4n. N/4. N4

Mathematics
1 answer:
Eva8 [605]3 years ago
8 0

Answer:

4n And N4 are the same Answer.. yet both mean 4 times n

You might be interested in
4. If A = (-4, -5) and B = (-1, -10), what is the length of segment AB? Round your answer to the nearest hundredth.
HACTEHA [7]

Answer:

5.83095 or √34

Step-by-step explanation:

Find the difference between coordinates:

(x2-x1) = (-1 - -4) = 3

(y2-y1) = (-10 - -5) = -5

Square the results and sum them up:

(3)2 + (-5)2 = 9 + 25 = 34

Now Find the square root and that's your result:

Exact solution: √34 = √34

Approximate solution: 5.831

7 0
3 years ago
What is the slope of a line that contains the points (2,-7) and (-1, -6)
Bogdan [553]

Answer:

Slope = - 1/3

Step-by-step explanation:

Y2-Y1 / X2 - X1

8 0
3 years ago
Which graph represents the function h(x) = -(x + 6)3 - 3?
katrin2010 [14]

Answer:

-8

Step-by-step explanation:

3 0
3 years ago
2. Solve x - 19 <81. Then graph the solution.
mr_godi [17]

Answer:

x<100

Step-by-step explanation:

The given equation is :

x-19<81

Adding 19 to both sides of the equation.

x-19+19<81+19

x<100

It means the solution of the given equation is less than 100. Hence, the attached figure shows the graph for the given equation.

4 0
3 years ago
Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr
Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

The first term of the sequence is at when n= 1

f(1) = 15(1)+4

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 15(2)+4

f(2) = 34

d = 34-19

d = 15

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)15)

S20 = 10(38+19(15))

S20 = 10(38+285)

S20 = 10(323)

S20 = 3230.

Sum of the 20th term is 3230

For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

d = 23-19

d = 4

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)4)

S20 = 10(38+19(4))

S20 = 10(38+76)

S20 = 10(114)

S20 = 1140

Sum of the 20th terms is 1140

7 0
3 years ago
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