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aleksklad [387]
3 years ago
12

The generic metal a forms an insoluble salt ab(s) and a complex ac5(aq). the equilibrium concentrations in a solution of ac5 wer

e found to be [a] = 0.100 m, [c] = 0.0110 m, and [ac5] = 0.100 m. determine the formation constant, kf, of ac5.
Chemistry
1 answer:
Leno4ka [110]3 years ago
3 0

Assuming that the reaction from A and C to AC5 is only one-step (or an elementary reaction) with a balanced chemical reaction of:

<span>A + 5 C  --->  AC5 </span>

Therefore the formation constant can be easily calculated using the following formula for formation constant:

Kf = product of products concentrations / product of reactants concentration

<span>Kf = [AC5] / [A] [C]^5                     </span>

---> Any coefficient from the balanced chemical reaction becomes a power in the formula

Substituting the given values into the equation:

Kf = 0.100 M / (0.100 M) (0.0110 M)^5

Kf = 6,209,213,231

or in simpler terms

<span>Kf = 6.21 * 10^9                  (ANSWER)</span>

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The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.

Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.

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So, from above relation it is found that 1 mole of any substance contains exactly 6.022 × 10²³ particles. Greater the number of moles greater will be the number of particles.
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