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Explanation:
It is given that,
Initially, the jogger is at rest u₁ = 0
He accelerates from rest to 4.86 m, v₁ = 4.86 m
Time, t₁ = 2.43 s
A car accelerates from u₂ = 20.6 to v₂ = 32.7 m/s in t₂ = 2.43 s
(a) Acceleration of the jogger :


a₁ = 2 m/s²
(b) Acceleration of the car,


a₂ = 4.97 m/s²
(c) Distance covered by the car,


d₁ = 5.904 m
Distance covered by the jogger,


d₂ = 64.73 m
The car further travel a distance of, d = 64.73 m - 5.904 m = 58.826 m
Hence, this is the required solution.
Answer:
88 m/s
Explanation:
To solve the problem, we can use the following SUVAT equation:

where
v is the final velocity
u is the initial velocity
a is the acceleration
d is the distance covered
For the car in this problem, we have
d = 484 m is the stopping distance
v = 0 is the final velocity
is the acceleration
Solving for u, we find the initial velocity:

<h2>
Answer: The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.</h2>
Explanation:
The half-life
of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.
In this case, we are given the half life of two elements:
beryllium-13: 
beryllium-15: 
As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?
We can find it out by the following expression:

Where
is the amount we want to find:


Finally:

Therefore:
The half-life of beryllium-15 is <u>400 times greater than</u> the half-life of beryllium-13.
Explanation:
1-How many moles of NazCOs are in 10.0 ml of a 2.0 M solution?
2-How many moles of NaCl are contained in 100.0 ml of a 0.20 M solution?
3- What weight (in grams) of H2SO4 would be needed to make 750.0 ml of
2.00 M solution?
4-What volume (in ml) of 18.0 M H2SO4 is needed to contain 2.45 g H2S04?