A $100 cart is moving down an inclined plane at 1.30 m/s. The cart collides with a stationary object and rebounds with a speed o
1 answer:
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Explanation:
It is given that,
Initially, the jogger is at rest u₁ = 0
He accelerates from rest to 4.86 m, v₁ = 4.86 m
Time, t₁ = 2.43 s
A car accelerates from u₂ = 20.6 to v₂ = 32.7 m/s in t₂ = 2.43 s
(a) Acceleration of the jogger :
a₁ = 2 m/s²
(b) Acceleration of the car,
a₂ = 4.97 m/s²
(c) Distance covered by the car,
d₁ = 5.904 m
Distance covered by the jogger,
d₂ = 64.73 m
The car further travel a distance of, d = 64.73 m - 5.904 m = 58.826 m
Hence, this is the required solution.
Answer:
88 m/s
Explanation:
To solve the problem, we can use the following SUVAT equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
d is the distance covered
For the car in this problem, we have
d = 484 m is the stopping distance
v = 0 is the final velocity
is the acceleration
Solving for u, we find the initial velocity:
<h2>Answer: The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.</h2>
Explanation:
The half-life of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.
In this case, we are given the half life of two elements:
beryllium-13:
beryllium-15:
As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?
We can find it out by the following expression:
Where is the amount we want to find:
Finally:
Therefore:
The half-life of beryllium-15 is <u>400 times greater than</u> the half-life of beryllium-13.