We r made of atom so v can’t touch anything hehe I just joking
If <em>v(t)</em> is speed measured in meters per second (m/s), and <em>t</em> is time measured in seconds (s), then the constants <em>A</em> and <em>B</em> in
<em>v(t)</em> = <em>At</em> ³ - <em>Bt</em>
must have units of m/s⁴ and m/s², respectively; otherwise, the equation is dimensionally inconsistent.
[m/s] = <em>A</em> [s]³ - <em>B</em> [s]
[m/s] = [m/s⁴] [s]³ - [m/s²] [s]
[m/s] = [m/s] - [m/s]
[m/s] = [m/s]
Answer:
3.24 m/s
Explanation:
Suppose that the boat sails with velocity (relative to water) direction being perpendicular to water stream. Had there been no water flow, it would have ended up 0m downstream
Therefore, the river speed is the one that push the boat 662 m downstream within 539 seconds. We can use this to calculate its magnitude

So the boat velocity vector relative to the bank is the sum of of the boat velocity vector relative to the water and the water velocity vector relative to the bank. Since these 2 component vectors are perpendicular to each other, the magnitude of the total vector can be calculated using Pythagorean formula:
m/s
To find the maximum height we use the expression:
U²=2gh
Where u is the initial velocity,
g is gravitational field strength
h is the maximum height.
h=u²/2g
h=40²/20
=1600/20
=80m