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jenyasd209 [6]
3 years ago
14

If a = 5^x, b = 5^y and a^y×b^x = 25 then prove that: xy =1​

Mathematics
1 answer:
avanturin [10]3 years ago
3 0

a =  {5}^{x}  \\ b =  {5}^{y}  \\  {a}^{y}  \times  {b}^{y}  = 25 \\ prove \: ( {5}^{x} )^{y}  \times ( {5}^{y} ) ^{x}  = 25 \\  {5}^{xy}  \times  {5}^{yx}  = {5}^{2} \\  {5 }^{xy + yx}  = 5^{2}  \\ 5^{2xy}  =  {5}^{2} \\ is \:  \: 2xy = 2 \\ xy =  \frac{2}{2}  \\ xy = 1

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PLS HELP ASAP! GIVING BRAINLIST!
castortr0y [4]

Answer: 5\sqrt{11}

Step-by-step explanation:

25*11=275

\sqrt{25}\sqrt{11}

25 is perfect square but 11 is not so 11 stays inside the radical while 25 is changed to 5

4 0
3 years ago
In May 1998, forest fires in southern Mexico and Guatemala spread smoke all the way to Austin. Those fires consumed forest land
liberstina [14]

Answer:

On average the size of the area of the forest burnt down every minute is 10117.14 m²

Step-by-step explanation:

The given parameters are;

The rate consumption of forest land by the fire = 25200 acres/week

Therefore, we have;

The number of minutes in one week = 60 × 24 × 7 = 10080 minutes

Therefore;

The rate consumption of forest land by the fire per minute = 25200/10080 acres/minute = 2.5 acres/minute

The number of square meters in one acre is given as follows;

1 acre = 4,046.856 m²

Therefore;

2.5 acres/minute = (2.5 × 4,046.856 m²/(1 acre)) acres/minute = 10117.14 m²/minute

Which give;

The rate consumption of forest land by the fire= 10117.14 m²/minute.

The rate of the fire consumption of the forest is 10117.14 m²/minute.

7 0
3 years ago
6+6y=-30 solve for y​
kakasveta [241]

Answer:

y = -6

Step-by-step explanation:

6 + 6y = -30

6y = -30 - 6

6y = -36

y = -6

7 0
3 years ago
The gas co2 is diffusin at steady state through a tube 20 cm long having a diameter of 1 cm and containing n2 at 350 k . the tot
Marrrta [24]

The value is J = 1.71*10^-6 kmol/m^2.s

According to the given conditions we get,

The length the tube l= 0.20m

The diameter of the tube d= 0.01m

The total pressure inside the tube P= 101.32kPa

The partial pressure of CO2 at the first end is

P1= 456mm Hg = 60794.832 Pa

The partial pressure of CO2 at the other end is

P2= 76mm Hg = 10132.472 Pa

The temperature is T = 298 K

The diffusion coefficient D= 1.67* 10^-5 m^2/s

Generally the molar flux of CO2 is mathematically represented as

J= D{p1-p2} / R.T

Here R is the gas constant with value R= 8.314 j/kmol

So we get J= 1.71 * 10^-3 mol/m^2.sec

Learn more about Mole on:

brainly.com/question/27270616

#SPJ4

       

       

4 0
2 years ago
1800 over 100 simplified
Sunny_sXe [5.5K]
1800 over 100 simplified is 18 over 1
5 0
3 years ago
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