1. A ball of mass 3kg is placed in a catapult which is pulled back by
1 answer:
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Answer:
Impulse is 1.239 kg.m/s in upward direction
Explanation:
Taking upward motion as positive and downward motion as negative.
Downward motion:
Given:
Mass of ball (m) = 0.150 kg
Displacement of ball (S) = -1.25 m
Initial velocity (u) = 0 m/s
Acceleration is due to gravity (g) = -9.8 m/s²
Using equation of motion, we have:
Since, the motion is downward, final velocity must be negative. So,
Upward motion:
Given:
Displacement of ball (S) = 0.665 m
Initial velocity () = 4.95 m/s(Upward direction)
Acceleration is due to gravity (g) = -9.8 m/s²
Using equation of motion, we have:
Since, the motion is upward, final velocity must be positive. So,
Now, impulse is equal to change in momentum. So,
Impulse = Final momentum - Initial momentum
Therefore, the impulse given to the ball by the floor is 1.239 kg.m/s in upward direction.
Answer:
Terminal velocity of object = 12.58 m/s
Explanation:
We know that the terminal velocity is attained when drag force and gravitational force are of the same magnitude.
Gravitational force = mg = 80 * 9.8 = 784 N
Drag force =
Equating both, we have
So v = 12.58 m/s or v = -15.58 m/s ( not possible)
So terminal velocity of object = 12.58 m/s