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Leona [35]
2 years ago
15

What is Potentiometer ​

Physics
1 answer:
Katena32 [7]2 years ago
3 0

Answer:

an instrument for measuring an electromotive force by balancing it against the potential difference produced by passing a known current through a known variable resistance.

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A tortoise and hare start from rest and have a race. As the race begins, both accelerate forward. The hare accelerates uniformly
never [62]

Answer:

1) Vf = 3.36 m/s

2) v = 6.86 m/s

3) s = 92.3 m

4) a = - 0.23 m/s²

Explanation:

1)

We use first equation of motion in this case:

Vf = Vi + at

where,

Vf = Final velocity = ?

Vi = Initial velocity = 0 m/s

a = acceleration = 1.4 m/s²

t = time = 2.4 s

Therefore,

Vf = 0 m/s + (1.4 m/s²)(2.4 s)

<u>Vf = 3.36 m/s</u>

2)

We again use first equation of motion but with t= 4.9 s now:

Vf = 0 m/s + (1.4 m/s²)(4.9 s)

Vf = 6.86 m/s

Now, this velocity remained constant for net 11 seconds. Hence, the velocity of hare after 8.9 s is:

<u>v = 6.86 m/s</u>

3)

First we use second equation of motion to find distance covered in accelerated motion:

s₁ = Vi t + (0.5)at²

s₁ = (0 m/s)(4.9 s) + (0.5)(1.4 m/s²)(4.9 s)²

s₁ = 16.8 m

Now, we calculate the distance covered in uniform motion:

s₂ = vt

s₂ = (6.86 m/s)(11 s)

s₂ = 75.5 m

Now, total distance covered before slowing down is given as:

s = s₁ + s₂ = 16.8 m + 75.5 m

<u>s = 92.3 m</u>

3)

Using third equation of motion for the decelerated motion:

2as = Vf² - Vi²

where,

a = deceleration = ?

s = distance covered = 102 m

Vf = Final Speed = 0 m/s

Vi = Initial Speed = 6.86 m/s

Therefore,

(2)(a)(102 m) = (0 m/s)² - (6.86 m/s)²

a = - (47.06 m²/s²)/(204 m)

<u>a = - 0.23 m/s²</u>

3 0
3 years ago
The magnetic dipole moment of Earth has magnitude 8.00 1022 J/T.Assume that this is produced by charges flowing in Earth’s molte
ziro4ka [17]

Answer:

2.08\cdot 10^9 A

Explanation:

The magnetic dipole moment of a circular coil with a current is given by

\mu = IA

where

I is the current in the coil

A=\pi r^2 is the area enclosed by the coil, where

r is the radius of the coil

So the magnetic dipole moment can be rewritten as

\mu = I\pi r^2 (1)

Here we can assume that the magnetic dipole moment of Earth is produced by charges flowing in Earth’s molten outer core, so by a current flowing in a circular path of radius

r=3500 km = 3.5\cdot 10^6 m

Here we also know that the Earth's magnetic dipole moment is

\mu = 8.0\cdot 10^{22} J/T

Therefore, we can re-arrange eq (1) to find the current that the charges produced:

I=\frac{\mu}{\pi r^2}=\frac{8.00\cdot 10^{22}}{\pi (3.5\cdot 10^6)^2}=2.08\cdot 10^9 A

3 0
3 years ago
A 15 kg mass is lifted to a height of 2m. What is gravitational potential energy at this position
7nadin3 [17]

Answer: 294J

Explanation:

U_g=mg(y_f-y_i)

U_g=(15)(9.8)(2-0)=294J

7 0
3 years ago
Read 2 more answers
Two 90.0-kilogram people are separated by 3.00 meters. What is the magnitude of the gravitational force that one person exerts o
VARVARA [1.3K]

Answer:

the magnitude of gravitational force is 6 x 10⁻⁸ N.

Explanation:

Given;

mass of the two people, m₁ and m₂ = 90 kg

distance between them, r = 3.0 m

The magnitude of gravitational force exerted by one person on another is calculated as;

F = \frac{Gm_1m_2}{r^2} \\\\

where;

G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²

F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{6.67\times 10^{-11} \times \ 90 \ \times \ 90}{3^2} \\\\F = 6\times 10^{-8} \ N

Therefore, the magnitude of gravitational force is 6 x 10⁻⁸ N.

4 0
3 years ago
A 60.0 kg girl stands up on a stationary floating raft and decides to go into shore. She dives off the 180 kg floating raft with
lord [1]
Momentum, p = m.v
m of the girl = 60.0 kg
m of the boat = 180 kg
v of the girl = 4.0 m/s

A) Momentum of the girl as she is diving:
p = m.v = 60.0 kg * 4.0 m/s = 24.0 N/s

B) momentum of the raft = - momentum of the girl = -24.0 N/s

C) speed of the raft

p = m.v ; v = p/m = 24.0N/s / 180 kg = -0.13 m/s [i.e. in the opposite direction of the girl's velocity]
6 0
3 years ago
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