Answer:
d) Law of Conservation of Energy
Explanation:
The first law of thermodynamics states that energy can neither be created nor destroyed; energy can only change from one form to another.
For multiple choice you can use an elimination method. If you remember the law then you know it's not A or C because "energy cannot be created nor destroyed", and it's not B because it has nothing to do with mass.
Hope this helps!
Answer:
14.7 m/sec.
Explanation:
We will go about using the mathematical formula,
Vf - Vo = gT.
To break it down,
Vf = Velocity of the apple just before hitting the ground.
Vo = Initial velocity of apple = 0
T = Time for apple to hit the ground = 1.5 sec
g = Acceleration due to gravity = 9.8 m/sec^2
We then need to substitute appropriate values,
<em>Vf - 0 = 9.8(1.5) </em>
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<em>Vf = 14.7 m/sec. </em>
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Answer:
Explanation:
We have given the mass of the carbon =0.1 kg
Molar mass of the carbon =12 gram
Number of moles
We know that 1 mole of carbon contain
So atoms contained by 8.333 moles
In question it is given that each atom contain 6 proton so number of proton
Now we know that each proton contain positive charge of
So total charge
Answer:
yes
Explanation:
because when you shot the ball your applying force to it
Answer:
c. Rock, metal, and ices made of materials like water, ammonia, and methane condensed into a solid and grew large enough to gravitationally attract hydrogen and helium gas from the Solar Nebula.
Explanation:
Given the information about dependence of planetesimal composition on distance from the Sun and the existence of the frost line resulted in two main types of planets in our Solar System: the inner rocky planets and the outer gas giants. I have learned that planetesimal formation through accretion, and the types of materials that condensed at that distance from the Sun, will lead to the formation of Rock, metal, and ices made of materials like water, ammonia, and methane condensed into a solid and grew large enough to gravitationally attract hydrogen and helium gas from the Solar Nebula.