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castortr0y [4]
3 years ago
13

Everyone who is thin is in shape. A. True B. False

Chemistry
1 answer:
MAVERICK [17]3 years ago
7 0

Answer:

false; one could be in thin shape but thay doesnt always mean they are healthy, or fit...there is always a chance there can be malnutrition or they have a good metabolism, but to be in shape, there should be a good balance of fat and muscle in the body

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R indicates round seeds that are dominant over the wrinkled variety represented by R for each numbered individual in the pedigre
hichkok12 [17]

Answer:

Explanation:X and Y

4 0
3 years ago
How do the numbers of metal and non-metal elements compare? Estimate an approximate percentage difference.
Lerok [7]

Answer:

metal to non metal ratio is 97/21 = 4.62 or

82.2% metals, 17.8% non metals

Explanation:

How do the numbers of metal and non-metal elements compare? Estimate an approximate percentage difference. (learning about the periodic table if...

of 118 elements in the periodic table , 21 are non metals (even H has metallic properties when approching 0 degrees K)

this means there ar 21 nonmetals and 118-21=97 metals.

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3 years ago
While the reaction in the lab text gives the product 4-methylcyclohexene, it is possible that several products are formed in thi
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Answer:

Explanation:

The step wise reaction mechanism for the formation of 1-methylcyclohexene is as follows.

6 0
3 years ago
La formula quimica de la molecula de agua H20 , si H = 1 gramos y O = 16 gramos . Cual es su composicion porcentual ? 88,88 % de
vesna_86 [32]

Answer:

88,88 % de O y 11,11 % de H

Explanation:

La composición porcentual se define como la masa que hay de cada mol de átomo en 100g. Las moles de agua en 100g son:

<em>Masa molar agua:</em>

2H = 2*1g/mol = 2g/mol

1O = 1*16g/mol = 16g/mol

Masa molar = 2 + 16 = 18g/mol

100g H2O * (1mol / 18g) = 5.556 moles H2O.

Moles de hidrógeno:

5.556 moles H2O * (2mol H / 1mol H2O) = 11.11 moles H

Moles Oxígeno = Moles H2O = 5.556 moles

La masa de hidrógeno es:

11.11mol * (1g/mol) 11.11g H

La masa de oxígeno es:

5.556 mol * (16g / 1mol) = 88.89g O

Así, el porcentaje de O es 88.89% y el de H es 11.11%. La opción correcta es:

<h3>88,88 % de O y 11,11 % de H</h3>
7 0
3 years ago
Write a complete, balanced equation for the following reactions:
lys-0071 [83]

Answer:

Solution given:

c) Magnesium metal plus silver acetate (teachers note:

<u>Balanced</u><u> </u><u>chemical</u><u> </u><u>equation</u><u>:</u>

\boxed{\bold{\green{Mg+AgC_{2}H_{3}O_{2}\rightarrow MgC_{3}H_{3}O_{2}+Ag^{+}}}}

d) hydrobromic acid plus zinc metal (teachers note:

<u>Balanced chemical equation:</u>

\boxed{\bold{\green{2HBr+Zn \rightarrow Be_{2}+H_{2}}}}

6 0
3 years ago
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