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MrRa [10]
3 years ago
6

1.Light waves (shown) are an example of what type of wave? (Lesson 4.03)

Chemistry
1 answer:
lesya692 [45]3 years ago
6 0

Answer:

<em>suface wave</em>

Explanation:

<em>hope this helps </em>

<em></em>

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A state property X has a value 89.6 units. It undergoes the following changes, first increase by
yanalaym [24]

Answer:

B) -4.1 units

Explanation:

According to this question, a state property X has a value 89.6 units. It undergoes the certain changes as follows:

- first increase by 3.6 units

- then increase by another 18.7 units

- then decrease by 12.2 units

- and finally attains a value of 85.5 units

This can be mathematically represented by 89.6 - {3.6 + 18.7 - 12.2 - x) = 85.5

To get x, we say;

89.6 + 3.6 = 93.2

93.2 + 18.7 = 111.9

111.9 - 12.2 = 99.7

99.7 - 85.5 = 14.2units.

The changes that occured is represented as follows:

= (3.6 + 18.7) - (12.2 + 14.2)

= 22.3 - 26.4

= -4.1 units

7 0
3 years ago
Which of the following would be a clue that a rock is sedimentary?​
Masteriza [31]
I do not see any possible answers that you have posted. But a good idea would be that it might have fossils, water currents, mud cracks, usually form in shallow seas. Hope this helps!
8 0
2 years ago
Read 2 more answers
How do valence electrons interact between non polar covalent, polar covalent, and ionic bonds?​
iVinArrow [24]

Answer:

In non-polar covalent bonds, the electrons are equally shared between the two atoms. For atoms with differing electronegativity, the bond will be a polar covalent interaction, where the electrons will not be shared equally.

Explanation:

i did some reasherch so there^^

5 0
2 years ago
For the reaction N2(g) + 2H2(g) → N2H4(l), if the percent yield for this reaction is 100.0%, what is the actual mass of hydrazin
barxatty [35]

Answer:

53.6 g of N₂H₄

Explanation:

The begining is in the reaction:

N₂(g) + 2H₂(g) → N₂H₄(l)

We determine the moles of each reactant:

59.20 g / 28.01 g/mol = 2.11 moles of nitrogen

6.750 g / 2.016 g/mol = 3.35 moles of H₂

1 mol of N₂ react to 2 moles of H₂

Our 2.11 moles of N₂ may react to (2.11 . 2) /1 = 4.22 moles of H₂, but we only have 3.35 moles. The hydrogen is the limiting reactant.

2 moles of H₂ produce at 100 % yield, 1 mol of hydrazine

Then, 3.35 moles, may produce (3.35 . 1)/2 = 1.67 moles of N₂H₄

Let's convert the moles to mass:

1.67 mol . 32.05 g/mol = 53.6 g

4 0
3 years ago
Use the Debye-Huckel Equation to calculate the activity coefficient of Ce4+ at μ = 0.070 M.
Dmitriy789 [7]

english please so i can help

8 0
3 years ago
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