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Annette [7]
3 years ago
7

A 0.530 M Ca(OH)2 solution was prepared by dissolving 36.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol

ution thus formed?
Chemistry
1 answer:
Gekata [30.6K]3 years ago
3 0

Answer:

0.917

Explanation:

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H2O+O2=H202, how would I balance this equation?
Sergio [31]

Answer:

2H2O2→2H2O+O2

Explanation:

This reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

Add 2 molecules of hydrogen peroxide and 2 molecules of water. Since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

2H2O2→2H2O+O2

8 0
3 years ago
To indicate the pH of a substance, one can use a dye that is both an acid and that appears as different colors in its protonated
PIT_PIT [208]

Answer:

<em>The pH of the solution is 7.8</em>

Explanation:

The concentration of the solution is 0.001M and  the dye could be in its protonated and deprotonated forms. If the concentration of the protonated form [HA] is 0.0002 M the concentration of the deprotonated form will be the subtraction between the concentration of the bye and the concentration of the protonated form:

[A-] = 0.001M - 0.0002M = 0.0008M

Also, the Henderson-Hasselbalch equation is

pH = pKa + Log \frac{[A^{-}]}{[HA]}

this equation shows the dependency between the pH of the solution, the pKa and the concentration of the protonated and deprotonated forms. Thus, replacing in the equation

pH = 7.2 + Log \frac{0.0008M}{0.0002M} = 7.8

3 0
3 years ago
How many grams of Cl are in 525g of CaCl2
Tema [17]

First we determine the moles CaCl2 present:

525g / (110.9g/mole) = 4.73 moles CaCl2 present 

Based on stoichiometry, there are 2 moles of Cl for every mole of CaCl2:<span>
(2moles Cl / 1mole CaCl2) x 4.73 moles CaCl2 = 9.47 moles Cl </span>

Get the mass:<span>
<span>9.47moles Cl x 35.45g/mole = 335.64 g Cl</span></span>

8 0
3 years ago
What is the volume of 8.80 g of CH4 gas at STP?
Ann [662]

Answer:

12.32 L.

Explanation:

The following data were obtained from the question:

Mass of CH4 = 8.80 g

Volume of CH4 =?

Next, we shall determine the number of mole in 8.80 g of CH4. This can be obtained as follow:

Mass of CH4 = 8.80 g

Molar mass of CH4 = 12 + (1×4) = 12 + 4 = 16 g/mol

Mole of CH4 =?

Mole = mass/Molar mass

Mole of CH4 = 8.80 / 16

Mole of CH4 = 0.55 mole.

Finally, we shall determine the volume of the gas at stp as illustrated below:

1 mole of a gas occupies 22.4 L at stp.

Therefore, 0.55 mole of CH4 will occupy = 0.55 × 22.4 = 12.32 L.

Thus, 8.80 g of CH4 occupies 12.32 L at STP.

6 0
3 years ago
If the compound below is oxidized, the resulting product is ___. Select one: a. methane and propane b. butanal c. butanoic acid
Anvisha [2.4K]

The complete question is

If the compound below is oxidized, the resulting product is ___.

the compound given is Butanal

Select one:

a. methane and propane

b. butanal

c. butanoic acid

d. butane

Answer:

C. Butanoic Acid

Explanation:

When Butanal is oxidized using reagents like KMnO4, Tollens reagent etc.

When Aldehyde is oxidized corresponding Carboxylic Acid is produced

 Butanal →  Butanoic Acid

7 0
3 years ago
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