Explanation:
Let us assume that the ratio for the given reaction is 1:1.
Therefore, we will calculate the moles of 
as follows.
Moles of solution = molarity × volume (L)
= 0.0440 M × 0.014 L
= 0.000616 moles
Moles of excess EDTA = 0.000616 moles
Also, the initial moles of EDTA will be calculated as follows.
Total initial moles of EDTA = 0.0600 M × 0.025 L
= 0.0015
Therefore, moles of EDTA reacted with 
will be as follows.
= 0.0015 - 0.000616
= 0.00088 moles
Since, we have supposed a 1 : 1 ratio between and EDTA
.
So, moles of = 0.00088 moles
Now, we will calculate the molarity of as follows.
Molarity of solution = 
= 
= 0.015 M
Thus, we can conclude that the original concentration of the solution is 0.015 M.
Answer:
ACETYL-CoA, FADH
2 NADH
acetyl-CoA
Explanation: Beta oxidation of carbons of fatty acid acid molecules leads to the formation Acetyl-CoA, FADH and NADH.
The overall reaction for the process
Cn-acyl-CoA + FAD + NAD+
+ H
2O + CoA → Cn-2-acyl-CoA + FADH
2 + NADH + H+
+ acetyl-CoA.
formula of NADH is C21H27N7O14P2
formula of FADH is C27H35N9O15P2.
Both NADH(Nicotinamide adenine dinucleotide) and FADH( Flavin adenine dinucleotide) are
formular for Acetyl CoA IS C23H38N7O17P3S.
Beta oxidation is a breakdown process taking place in living systems which catabolises the fatty acids through glycolysis or fermentation leading to the release of Acetyl CoA, NADH AND FADH2.
Answer:
D
Explanation:
A single-replacement reaction occurs when one element replace another in a single compound.
