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Jobisdone [24]
3 years ago
9

Can you please help me

Chemistry
2 answers:
aleksandr82 [10.1K]3 years ago
8 0
Ionic compounds are made up of cations and anions.
So,  C would be the correct answer
Vlada [557]3 years ago
7 0
Jack would be the correct anwser ,, so c
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A powder contains FeSO4⋅7H2O (molar mass=278.01 g/mol), among other components. A 3.930 g sample of the powder was dissolved in
fredd [130]

Answer:

The mass of FeSO4*7H2O in the sample is 1.21 grams

Explanation:

<u>Step 1</u>: Calculate moles of Fe2O3

moles of Fe2O3 = mass of Fe2O3 / Molar mass of Fe2O3

moles of Fe2O3 = 0.348 grams / 159.69 g/mole = 0.00218 moles

<u>Step 2</u>: Calculate moles of Fe

4 Fe + 3O2 → 2Fe2O3

For 4 moles of Fe consumed there is 2 moles of Fe2O3 produced

This means it has a ratio 2:1

So 0.00218 moles of Fe2O3 produced , there is 2*0.00218 = 0.00436 moles of Fe consumed

<u>Step 3:</u> Calculate moles of FeSO4*7H2O

Fe + H2SO4 + 7H2O → FeSO4*7H20 + H2

For 1 mole of Fe consumed there is 1 mole of FeSO4*7H2O produced

This means for 0.00436 moles there is 0.00436 moles of Fe2SO4*H2O produced

<u>Step 4:</u> Calculate the mass of FeSO4*7H2O in the sample

mass of FeSO4*7H2O = 0.00436 moles * 278.01 g/mole = 1.212 g

The mass of FeSO4*7H2O in the sample is 1.21 grams

8 0
3 years ago
A 78.0 g sample of an unknown compound contains 12.4 g of hydrogen. what is the percent by mass of hydrogen in the compound?
AleksandrR [38]
Formula to find the percent composition of an element in a compound is \frac {MolarMassOfElement}{MolarMassOfCompound}*100.

Now enter the variables into the formula.

\frac {12.4}{78.0}*100 = 15.897%
Round to 3 significant figures. 15.897% = 15.9%

The answer is 15.9% H
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3 years ago
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Answer is attached  below ( sorry for mistake )

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Liula [17]

Answer is equal to 7.51 kJ

Q=mc(delta)T

4 0
2 years ago
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