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Molodets [167]
3 years ago
8

What is the electron configuration for a neutral atom of fluorine.

Chemistry
2 answers:
zavuch27 [327]3 years ago
6 0

Answer and Explanation: The full ground-state electron configuration for a fluorine atom is 1s2, 2s2, 2p5. We determine this by first identifying the number of electrons in a fluorine atom. If the atom is neutral, it will have nine electrons to match the nine protons int he fluorine nucleus

Minchanka [31]3 years ago
5 0

Answer:

The full ground-state electron configuration for a fluorine atom is 1s2, 2s2, 2p5.

Explanation:

We determine this by first identifying the number of electrons in a fluorine atom. If the atom is neutral, it will have nine electrons to match the nine protons int he fluorine nucleus.

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b) Si los ácidos nitroso y fluorhídrico están descritos como electrolitos débiles, ¿significa que en la disolución hay moléculas
viva [34]

Los electrolitos son sustancias que se disocian en agua para dar iones.

Generalmente en química, podemos clasificar sustancias como

  • Electrolitos
  • No electrolitos

Los electrolitos pueden disociarse en solución para producir iones, pero un no electrolito no puede hacer eso.

Entre los electrolitos hay dos clases;

  • Electrolitos fuertes
  • Electrolitos débiles

Los electrolitos fuertes se disocian completamente en solución, mientras que los electrolitos débiles no se disocian completamente en solución.

El hecho de que los electrolitos débiles no se disocien por completo significa que algunas moléculas de la sustancia no se disocian.

Por lo tanto, si los ácidos nitroso y fluorhídrico se describen como electrolitos débiles, esto significa que hay moléculas en la solución que no están disociadas.

Lea más: brainly.com/question/14566383

5 0
2 years ago
Which tempature is warmer than the freezing point in water?
vfiekz [6]
Water freezes at 0°C, 32°F, and 273°K. The only temperature warmer than the freezing point is 1°C.
7 0
3 years ago
Read 2 more answers
A sulfuric acid solution containing 571.3 g of h2so4 per liter of aqueous solution has a density of 1.329 g/cm3. Part a calculat
loris [4]

Mass percentage of a solution is the amount of solute present in 100 g of the solution.

Given data:

Mass of solute H2SO4 = 571.3 g

Volume of the solution = 1 lit = 1000 ml

Density of solution = 1.329 g/cm3 = 1.329 g/ml

Calculations:

Mass of the given volume of solution = 1.329 g * 1000 ml/1 ml = 1329 g

Therefore we have:

571.3 g of H2SO4 in 1329 g of the solution

Hence, the amount of H2SO4 in 100 g of solution= 571.3 *100/1329 = 42.987

Mass percentage of H2SO4 (%w/w) is 42.99 %

3 0
3 years ago
Help with this chemistry worksheet
viktelen [127]

Answer:

1. is exothermic

Explanation:

5 0
3 years ago
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Are protons and neutrons the same size? Explain.
Ivahew [28]

no because they are two diffrent things

4 0
3 years ago
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