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3 years ago

What is the electron configuration for a neutral atom of fluorine.

2 answers:

6 0

Answer and Explanation: The full ground-state electron configuration for a fluorine atom is 1s2, 2s2, 2p5. We determine this by first identifying the number of electrons in a fluorine atom. If the atom is neutral, it will have nine electrons to match the nine protons int he fluorine nucleus

Minchanka [31]3 years ago

5 0

Answer:

The full ground-state electron configuration for a fluorine atom is 1s2, 2s2, 2p5.

Explanation:

We determine this by first identifying the number of electrons in a fluorine atom. If the atom is neutral, it will have nine electrons to match the nine protons int he fluorine nucleus.

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3 years ago

When barium hydroxide and ammonium chloride react,the temperature of the mixture decreases.What kind of reaction is this?

GalinKa [24]

Answer:

Endothermic

Explanation:

7 0

3 years ago

In the first 15.0 s of the reaction, 1.9×10−2 mol of O2 is produced in a reaction vessel with a volume of 0.480 L . What is the

N76 [4]

The question is incomplete, here is the complete question:

Consider the following reaction: $2N_2O(g)\rightarrow 2N_2(g)+O_2(g)$

In the first 15.0 s of the reaction, 1.9×10⁻² mol of O₂ is produced in a reaction vessel with a volume of 0.480 L . What is the average rate of the reaction over this time interval?

<u>Answer:</u> The average rate of appearance of oxygen gas is $2.64\times 10^{-3}M/s$

<u>Explanation:</u>

We are given:

Moles of oxygen gas = $1.9\times 10^{-2}moles$

Volume of solution = 0.480 L

Molarity is calculated by using the equation:

$\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

So, $\text{Molarity of }O_2=\frac{1.9\times 10^{-2}mol}{0.480L}=0.0396M$

The given chemical reaction follows:

$2N_2O(g)\rightarrow 2N_2(g)+O_2(g)$

The average rate of the reaction for appearance of $O_2$ is given as:

$\text{Average rate of appearance of }O_2=\frac{\Delta [O_2]}{\Delta t}$

Or,

$\text{Average rate of appearance of }O_2=\frac{C_2-C_1}{t_2-t_1}$

where,

$C_2$ = final concentration of oxygen gas = 0.0396 M

$C_1$ = initial concentration of oxygen gas = 0 M

$t_2$ = final time = 15.0 s

$t_1$ = initial time = 0 s

Putting values in above equation, we get:

$\text{Average rate of appearance of }O_2=\frac{0.0396-0}{15-0}\\\\\text{Average rate of appearance of }O_2=2.64\times 10^{-3}M/s$

Hence, the average rate of appearance of oxygen gas is $2.64\times 10^{-3}M/s$

8 0

4 years ago

The point in a planet's orbit where it is farthest from the Sun is called the _____.

algol [13]

The answer is Aphelion since that is the point in a planet, comet or asteroids orbit around a sun when it is furthest

6 0

4 years ago

Where does the energy released by an earthquake come from?

Stella [2.4K]

Answer:

The energy released during the sudden ground motion comes from a build up over long periods of time, as a result of tectonic forces within the earth. Plate boundaries are made up of many faults. The edges of these faults are not smooth like a table top but are rough

Explanation:

thank you for the work

7 0

4 years ago