Answer:
44.7 kWh
Explanation:
Let's consider the reduction of Al₂O₃ to Al in the Bayer process.
6 e⁻ + 3 H₂O + Al₂O₃ → 2 Al + 6 OH⁻
We can establish the following relations:
- The molar mass of Al is 26.98 g/mol.
- 2 moles of Al are produced when 6 moles of e⁻ circulate.
- 1 mol of e⁻ has a charge of 96468 c (Faraday's constant).
- 1 V = 1 J/c
- 1 kWh = 3.6 × 10⁶ J
When the applied electromotive force is 5.00 V, the energy required to produce 3.00 kg (3.00 × 10³ g) of aluminum is:
Answer: H+ ia helyuim
explinanation: Hope this helped!!
I’m pretty sure it’s none of the above cause I’m googling it a bunch and and it say you use the dideoxy method
The required amount of KClO₃ to prepare a saturated solution is 48 grams.
<h3>What is solubility?</h3>
The ability of a material, the solute, to create a solution with another substance, the solvent, is known as solubility.
Given graph is plotted between the temperature and solubility of the substance at 100g of water, so for the given points calculation will be:
- According to the graph for the KClO₃ we require almost 48g of KClO₃ to prepare a saturated solution.
- From the graph it is clear that at 40°C 40g of KCl will dissolve in 100g of water then amount of KCl which will dissolve in 68g of water will be calculated as:
x = (40)(68) / (100) = 27.2g
- On the basis of the graph, if 75 grams of calcium chloride is added to 100 g of water at 25°C then the obtained solution is the unsaturated as they have les solute then the limit.
- Based on the graph cerium sulfate behaves like a precipitate which will not dissolve at any temperature and present in the physical state.
- We can add more 30g to make the KCl solution saturated.
Hence, we require almost 48g of KClO₃ to prepare a saturated solution of KClO₃.
To know more about solubility, visit the below link:
brainly.com/question/16903071
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