Explanation:
You have a solution that contains 36 g HCl dissolved in 64 g water
Molar mass HCl = 36.45 g/mol
Mol HCl in 36 g = 36 g / 36.45 g/mol = 0.9876 mol
Molar mass H2O = 18 g/mol
Mol H2O in 64 g = 64 g / 18 g/mol = 3.5556 mol
Total mol = 0.9875 + 3.5556 = 4.5431 mol
Mol fraction HCl = 0.9876 mol / 4.5431 mol = 0.2174
Mol fraction H2O = 3.5556 / 4.5431 = 0.7826
The answer should have 2 significant digits:
Mol fraction HCl = 0.22
Mol fraction H2O = 0.78
Mol fraction has no units.
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Answer:
the second answer
Explanation:
just multiple 10²=10×10=100×7.6=760g
Answer:
Since with LiBr no precipitation takes place. So, Ag+ is absent
When we add Li2SO4 to it, precipitation takes place.
Ca2+(aq) + SO42-(aq) ----> CaSO4(s) ...Precipitate
Thus, Ca2+ is present.
When Li3PO4 is added, again precipitation takes place.Reaction is:
Co2+(aq) + PO43-(aq)---->Co3(PO4)2(s) ... Precipitate
A. Ca2+ and Co2+ are present in solution
B. Ca2+(aq) + SO42-(aq) ----> CaSO4(s)
C. 3Co2+(aq) + 2PO43-(aq)---->Co3(PO4)2(s)
Answer:
I think im good at it i have an A in the class
Explanation:
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