All categories

3 years ago

Average velocity is different than average speed because calculating average velocity involves

Physics

2 answers:

Katyanochek1 [597]3 years ago

5 0

Average velocity is different than average speed because calculating average velocity involves Momentum.

podryga [215]3 years ago

3 0

Answer:

Displacement

Explanation:

We are given that average velocity is different than average speed.

We have to find what involves average velocity.

Average velocity:It is defined as the displacement per unit time.

Mathematical representation,

Average velocity= $\frac{displacement}{time}=\frac{ds}{dt}$

Average speed:It is defined as the distance per unit time.

Average speed= $\frac{distance}{time}=[tex]\frac{s}{t}$

Average velocity is different from average speed because calculating average velocity involves displacement but average speed involves distance.

You might be interested in

A resistor and an inductor are connected in series to a battery. The time constant for the circuit represents the time required

sattari [20]

E, 63% of the maximum current

5 0

4 years ago

An ideal monatomic gas initially has a temperature of T and a pressure of p. It is to expand from volume V1 to volume V2. If the

yawa3891 [41]

Answer:

Isothermal : P2 = ( P1V1 / V2 ) , work-done $pdv = nRT * In( \frac{V2}{v1} )$

Adiabatic : : P2 = $\frac{P1V1^{\frac{5}{3} } }{V2^{\frac{5}{3} } }$ , work-done =

W = $(3/2)nR(T1V1^(2/3)/(V2^(2/3)) - T1)$

Explanation:

initial temperature : T

Pressure : P

initial volume : V1

Final volume : V2

A) If expansion was isothermal calculate final pressure and work-done

we use the gas laws

= PIVI = P2V2

Hence : P2 = ( P1V1 / V2 )

work-done :

$pdv = nRT * In( \frac{V2}{v1} )$

B) If the expansion was Adiabatic show the Final pressure and work-done

final pressure

$P1V1^y = P2V2^y$

where y = 5/3

hence : P2 = $\frac{P1V1^{\frac{5}{3} } }{V2^{\frac{5}{3} } }$

Work-done

W = $(3/2)nR(T1V1^(2/3)/(V2^(2/3)) - T1)$

Where $T2 = T1V1^(2/3)/V2^(2/3)$

3 0

3 years ago

A duck is 12 m from the edge of a pond. A student stands in the middle of the pond

olganol [36]

Answer:

The wavelength is 2 meters

Explanation:

The relationship between the frequency, the speed and the wavelength is given by the relation;

v = f × λ

The given parameters are;

The distance of the duck from the edge of the pond = 12 m

The number of ripples produced per second = Frequency, f = 2 Hz

The time it takes the ripple to reach the edge of the pond after travelling past the duck = 3 seconds

Therefore, speed of the wave, v = Distance/time = 12 m/(3 s) = 4 m/s

The wavelength, λ, is therefore;

λ = v/f = (4 m/s)/(2 Hz) = 2 meters.

6 0

3 years ago

A stone is thrown downward with a speed of 8 m/s from a height of 14 m. (acceleration due to gravity: 10 m/s2) What is the speed

max2010maxim [7]

Answer:

The speed of the stone just before it hits the ground is 18.54 m/s

Explanation:

Given that,

Initial speed of the stone, u = 8 m/s

The stone is thrown downward from a height of 14 m

We need to find the speed of the stone just before it hits the ground. It can be calculated using third equation of motion as :

$v^2-u^2=2ah$

v is the speed of the stone just before it hits the ground

$v^2=2ah+u^2$

$v^2=2\times 10\times 14+(8)^2$

v = 18.54 m/s

So, the speed of the stone just before it hits the ground is 18.54 m/s. Hence, this is the required solution.

6 0

3 years ago

How do electromagnetic waves move through space?

lesantik [10]

Answer:through a small space through atoms

Explanation:

4 0

4 years ago