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Fittoniya [83]
2 years ago
9

Average velocity is different than average speed because calculating average velocity involves

Physics
2 answers:
Katyanochek1 [597]2 years ago
5 0
Average velocity is different than average speed because calculating average velocity involves Momentum.
podryga [215]2 years ago
3 0

Answer:

Displacement

Explanation:

We are given that average velocity is different than average speed.

We have to find what involves average velocity.

Average velocity:It is defined as the displacement per unit time.

Mathematical representation,

Average velocity=\frac{displacement}{time}=\frac{ds}{dt}

Average speed:It is defined as the distance per unit time.

Average speed=\frac{distance}{time}=[tex]\frac{s}{t}

Average velocity is different from average speed because calculating average velocity involves displacement but average speed involves distance.

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A large helium filled balloon is used as the center piece for a graduation party. The balloon alone has a mass of 222 kg and it
inn [45]

Answer:

The buoyant force is 3778.8 N in upward.

Explanation:

Given that,

Mass of balloon = 222 Kg

Volume = 328 m³

Density of air = 1.20 kg/m³

Density of helium = 0.179 kg/m³

We need to calculate the buoyant force acting

Using formula of buoyant force

F_{b}=\rho_{air}\times V_{b}\times g

Where, \rho_{air} = density of air

V = Volume of balloon

g = acceleration due to gravity

Put the value into the formula

F_{b}=1.20\times321\times9.81

F_{b}=3778.8\ N

This buoyant force is in upward direction.

Hence, The buoyant force is 3778.8 N in upward.

4 0
2 years ago
The order of elements in the periodic table is based on?
ahrayia [7]
It is based on atomic number, which is the number of protons in the nuclei of the atoms of an element.
3 0
3 years ago
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The coefficient of the restitution of an object is defined as the ratio of its outgoing to incoming speed when the object collid
IgorLugansk [536]

Answer:

48.16 %

Explanation:

coefficient of restitution = 0.72

let the incoming speed be = u

let the outgoing speed be = v

kinetic energy = 0.5 x mass x x velocity^{2}

  • incoming kinetic energy = 0.5 x m x x u^{2}

     

  •  coefficient of restitution =\frac{v}{u}

       0.72 =\frac{v}{u}

       v = 0.72u

        therefore the outgoing kinetic energy = 0.5 x m x (0.72u)^{2}

        outgoing kinetic energy = 0.5 x m x 0.5184 x u^{2}

        outgoing kinetic energy = 0.5184 (0.5 x m x x u^{2})

recall that 0.5 x m x x u^{2} is our incoming kinetic energy, therefore

outgoing kinetic energy = 0.5184 x (incoming kinetic energy)

from the above we can see that the outgoing kinetic energy is 51.84 % of the incoming kinetic energy.

The energy lost would be 100 - 51.84 = 48.16 %

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3 years ago
What is the momentum of a 50 at a speed of 5m/s
aleksandr82 [10.1K]
50*5=250
Momentum will be 250kgm/s^2
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2 years ago
Plzz Help worth 10 points!!! which statement about energy transformations is not true?
EleoNora [17]
I think it could be A
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