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Fittoniya [83]
3 years ago
9

Average velocity is different than average speed because calculating average velocity involves

Physics
2 answers:
Katyanochek1 [597]3 years ago
5 0
Average velocity is different than average speed because calculating average velocity involves Momentum.
podryga [215]3 years ago
3 0

Answer:

Displacement

Explanation:

We are given that average velocity is different than average speed.

We have to find what involves average velocity.

Average velocity:It is defined as the displacement per unit time.

Mathematical representation,

Average velocity=\frac{displacement}{time}=\frac{ds}{dt}

Average speed:It is defined as the distance per unit time.

Average speed=\frac{distance}{time}=[tex]\frac{s}{t}

Average velocity is different from average speed because calculating average velocity involves displacement but average speed involves distance.

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Calculate the critical angle for light going from Glycerine to air.
Georgia [21]
The refractive index for glycerine is n_g=1.473, while for air it is n_a = 1.00.

When the light travels from a medium with greater refractive index to a medium with lower refractive index, there is a critical angle over which there is no refraction, but all the light is reflected. This critical angle is given by:
\theta_c = \arcsin ( \frac{n_2}{n_1} )
where n1 and n2 are the refractive indices of the two mediums. If we susbtitute the refractive index of glycerine and air in the formula, we find the critical angle for this case:
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6 0
3 years ago
A body weights 50 N in air and 45 N when wholly immersed in water calculate (i) the loss in weight of the body in water (ii) the
Lelechka [254]

Answer:

difference  \: in \: weight = 150n - 100n = 50n

Now,buyantant force

difference \: in \: weight \: = volume(body) \times density \: of \: water \:  \times g

so;

50 =  {v}^{b}  \times 1 \times  {10}^{3}  \times 9.8m {s}^{2}

{v}^{b}  =  \frac{50}{1000 } \times 9.8

=  \frac{50}{9800}

= 0.0051

Now,

mass \: in \: air \:  = 150n =  \frac{150}{9.8kg}

density =  \frac{weght}{volume}

=  \frac{150}{0.0051}  \times 9.8 \\ x = 3000

And now,

specific \: density \:  =  \frac{density of \: the \: body}{density \: of \: water}

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= 3

Hence that,specific density of a given body is 3

please mark me as brainliest, please

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3 years ago
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