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Fittoniya [83]
3 years ago
9

Average velocity is different than average speed because calculating average velocity involves

Physics
2 answers:
Katyanochek1 [597]3 years ago
5 0
Average velocity is different than average speed because calculating average velocity involves Momentum.
podryga [215]3 years ago
3 0

Answer:

Displacement

Explanation:

We are given that average velocity is different than average speed.

We have to find what involves average velocity.

Average velocity:It is defined as the displacement per unit time.

Mathematical representation,

Average velocity=\frac{displacement}{time}=\frac{ds}{dt}

Average speed:It is defined as the distance per unit time.

Average speed=\frac{distance}{time}=[tex]\frac{s}{t}

Average velocity is different from average speed because calculating average velocity involves displacement but average speed involves distance.

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Two long, straight wires are separated by 0.120 m. The wires carry currents of 11 A in opposite directions, as the drawing indic
rewona [7]

Answer:

The magnitude of the magnetic field is 1.83 x 10^{-5} T.

Explanation:

The flow of an electric current in a straight wire induces magnetic field around the wire. When current is flowing through two wires in the same direction, a force of attraction exists between the wires. But if the current flows in opposite directions, the force of repulsion is felt by the wires.

In the given question, the direction of flow of current through the wires is opposite, thus both wires applies the same field on each other. The result to repulsion between them.

The magnetic field (B) between the given wires can be determined by:

B = \frac{U_{o}I }{2\pi r}

where: I is the current, r is the distance between the wires and U_{0} is the magnetic field constant.

But, I = 11 A, r = 0.12 m and U_{0} = 4\pi x 10^{-7} Tm/A

So that;

B = \frac{4\pi *10^{-7}*11 }{2\pi *0.12}

   = 1.8333 x 10^{-5}

B = 1.83 x 10^{-5} T

6 0
2 years ago
A solid ball is released from rest and slides down a hillside that slopes downward at 65.0" from the horizontal
PilotLPTM [1.2K]
Setting reference frame so that the x axis is along the incline and y is perpendicular to the incline 
<span>X: mgsin65 - F = mAx </span>
<span>Y: N - mgcos65 = 0 (N is the normal force on the incline) N = mgcos65 (which we knew) </span>
<span>Moment about center of mass: </span>
<span>Fr = Iα </span>
<span>Now Ax = rα </span>
<span>and F = umgcos65 </span>
<span>mgsin65 - umgcos65 = mrα -------------> gsin65 - ugcos65 = rα (this is the X equation m's cancel) </span>
<span>umgcos65(r) = 0.4mr^2(α) -----------> ugcos65(r) = 0.4r(rα) (This is the moment equation m's cancel) </span>
<span>ugcos65(r) = 0.4r(gsin65 - ugcos65) ( moment equation subbing in X equation for rα) </span>
<span>ugcos65 = 0.4(gsin65 - ugcos65) </span>
<span>1.4ugcos65 = 0.4gsin65 </span>
<span>1.4ucos65 = 0.4sin65 </span>
<span>u = 0.4sin65/1.4cos65 </span>
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3 years ago
An electric generator transforms mechanical energy into electrical energy. This process could be done by which of these?
Dimas [21]

Answer:

its d

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A long, straight wire lies in the plane of a circular coil with a radius of 0.018 m. the wire carries a current of 5.6 a and is
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\Phi = BA \cos \theta
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How deep is the outer core beneath the surface
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