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gregori [183]
3 years ago
11

What is the volume of 80.0 g of ether if the density is 0.70 g/ml

Chemistry
1 answer:
My name is Ann [436]3 years ago
6 0
I need to find the x pls help and show work 73838
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What is the molecular formula of the hydrocarbon whose molar mass is 536 g/mol and contains 89.55 w/w% carbon?
leonid [27]

Given the percentage composition of HC as C → 81.82 % and H → 18.18 %

So the ratio of number if atoms of C and H in its molecule can will be:

C : H = 81.82 12 : 18.18 1 C : H = 6.82 : 18.18 = 6.82 6.82 : 18.18 6.82 = 1 : 2.66 ≈ 3 : 8

So the Empirical Formula of hydrocarbon is:

C 3 H 8

As the mass of one litre of hydrocarbon is same as that of C O 2 The molar mass of the HC will be same as that of C O 2 i.e 44 g mol

Now let Molecular formula of the HC be ( C 3 H 8 ) n

Using molar mass of C and H the molar mass of the HC from its molecular formula is:

( 3 × 12 + 8 × 1 ) n = 44 n So 44 n = 44 ⇒ n = 1

Hence the molecular formula of HC is C 3 H 8

Does that help?

7 0
3 years ago
How many atoms are in 1.204x10^22 moles of arsenic?
ra1l [238]

Answer:

<h2>0.02 moles </h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

n =  \frac{1.204 \times  {10}^{22} }{6.02 \times  {10}^{23} }    \\  = 0.02

We have the final answer as

<h3>0.02 moles</h3>

Hope this helps you

7 0
3 years ago
Paliwanag ang kahalagahan ng papa at ng holy roman emperor sa panahong midieval.
Doss [256]

Explanation:

The Holy Roman Empire (Latin: Sacrum Imperium Romanum; German: Heiliges Römisches Reich), also termed as the First Reich, was a multi-ethnic complex of territories in Western and Central Europe that developed during the Early Middle Ages and continued until its dissolution in 1806 during the Napoleonic Wars.[6] The largest territory of the empire after 962 was the Kingdom of Germany, though it also included the neighboring Kingdom of Bohemia and Kingdom of Italy, plus numerous other territories, and soon after the Kingdom of Burgundy was added. However, while by the end of the 15th century the Empire was still in theory composed of three major blocks – Italy, Germany, and Burgundy – in practice only the Kingdom of Germany remained, with the Burgundian territories lost to France and the Italian territories, ignored in the Imperial Reform, although formally part of the Empire, were splintered into numerous de facto independent territorial entities.[7][8][9][10] The external borders of the Empire did not change noticeably from the Peace of Westphalia – which acknowledged the exclusion of Switzerland and the Northern Netherlands, and the French protectorate over Alsace – to the dissolution of the Empire. By then, it largely contained only German-speaking territories, plus the Kingdom of Bohemia, the southern Netherlands and lands of Carniola. At the conclusion of the Napoleonic Wars in 1815, most of the Holy Roman Empire was included in the German Confederation.

in yr language:

Ang Holy Roman Empire (Latin: Sacrum Imperium Romanum; German: Heiliges Römisches Reich), na tinawag din bilang First Reich, ay isang multi-etniko na kumplikado ng mga teritoryo sa Kanluran at Gitnang Europa na d

3 0
3 years ago
0.2640 g of sodium oxalate is dissolved in a flask and requires 30.74 mL of potassium
Free_Kalibri [48]

Moles of potassium permanganate = 0.0008

<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range  

Reaction

5Na2C2O4(aq) + 2KMnO4(aq) + 8H2SO4(aq) ---> 2MnSO4(aq) + K2SO4(aq) + 5Na2SO4(aq) +  10CO2(g) + 8H2O(1)

The end point ⇒titrant and analyte moles equal

titrant : potassium  permanganate-KMnO4

analyte : sodium oxalate - Na2C2O4

so moles of KMnO4 = moles of Na2C2O4

moles of Na2C2O4(mass = 0.2640 g, MW=134 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{0.264}{134 g/mol}\\\\mol=0.002

From equation, mol ratio  Na2C2O4 : KMnO4 = 5 : 2, so mol KMnO4 :

\tt \dfrac{2}{5}\times 0.002=0.0008

6 0
3 years ago
In water, hydrogen bonds are best described as _____.
Elina [12.6K]

Answer: Option D) covalent bonds between water molecules

In water, hydrogen bonds are best described as covalent bonds between water molecules

Explanation:

The hydrogen bonds between water molecules are covalent bonds because they are formed when oxygen attract the lone electron in hydrogen, thus resulting in the formation of a partially negative charge on the oxygen atom and a partially positive charge on two hydrogen atoms

Thus, the sharing of electrons between oxygen and hydrogen atoms is responsible for the covalent bonds between water molecules

7 0
3 years ago
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