Answer:
67.492cm^3
Explanation:
To get the volume of tetrahydrofuran needed, what the student need to do is to apply mathematical calculations.
We know quite well that to obtain the volume of a substance, given the mass of the substance and the density of the substance is possible.
The volume of the substance is simply the mass of the substance divided by the density of the substance.
This is thus volume = mass/density
The mass given is the question is 60g while the density given is 0.889g/cm^3
The volume = 60/0.889 = 67.492cm^3
Answer:
the pressure would be 0.9 atmospheres
Explanation:
you just gotta add the presures for each of the gases that are added
Answer:
Mass percent of food dyes = 0.0616%
Explanation:
Given data:
Mass of candy = 47.9 g
Calories = 240
Mass of fat = 10 g
Mass of carbohydrate = 34 g
Mass of protein = 2 g
Mass of food dyes = 29.5 mg
Mass percent of food dyes = ?
Solution:
First of all we will convert the mg into g.
Mass of food dyes = 29.5 mg × 1g /1000 mg = 0.0295 g
Mass percent of food dyes = mass of food dyes / total mass× 100
Now we will put the values.
Mass percent of food dyes = 0.0295 g / 47.9 g × 100
Mass percent of food dyes = 0.000616 × 100
Mass percent of food dyes = 0.0616%
Scientist rely on their estimates when they cannot obtain on exact numbers
