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Oksanka [162]
3 years ago
14

A 7kg bowling ball is at rest at the end of a bowling lane. You push the ball with a force of 22N which induces a -1N of frictio

n force so the ball
accelerates 3m/s/s. What is the net force acting on the ball?
Physics
1 answer:
Valentin [98]3 years ago
7 0

Explanation:

You can find the net force by summing the force components:

∑F = 22 N − 1 N

∑F = 21 N

Or by using Newton's second law:

∑F = ma

∑F = (7 kg) (3 m/s²)

∑F = 21 N

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A +0.2 µC charge is in an electric field. What happens if that charge is replaced by a +0.4 µC charge?
AleksandrR [38]

Explanation:

It is known that electric field is responsible for creating electric potential. As a result, it depends only on the electric field and not on the magnitude of charge.

So, when a charge is increased by a factor of 2 then electric potential will remain the same. Since, expression to calculate the electric potential is as follows.

                 U = qV

Since, the electric potential is directly proportional to the charge. Hence, when 0.2 \mu C tends to replaced by 0.4 \mu C then charge is increased by a factor of 2. Hence, the electric potential energy is doubled.

Thus, we can conclude that if that charge is replaced by a +0.4 µC charge then electric potential stays the same, but the electric potential energy doubles.

4 0
3 years ago
Does anyone know how to solve series parallel and combo circuits
tamaranim1 [39]

Answer:

Your teacher is out of her/his mind, what is he thinking

Explanation:

my dear friend, i feel sorry for you, poor thing T_T

5 0
3 years ago
A disk 7.90 cm in radius rotates at a constant rate of 1 190 rev/min about its central axis. (a) Determine its angular speed. 12
Tanya [424]

Answer:

124.62\ \text{rad/s}

3.71\ \text{m/s}

1.23\ \text{km/s}^2

20.28\ \text{m}

Explanation:

r = Radius of disk = 7.9 cm

N = Number of revolution per minute = 1190 rev/minute

Angular speed is given by

\omega=N\dfrac{2\pi}{60}\\\Rightarrow \omega=1190\times \dfrac{2\pi}{60}\\\Rightarrow \omega=124.62\ \text{rad/s}

The angular speed is 124.62\ \text{rad/s}

r = 2.98 cm

Tangential speed is given by

v=r\omega\\\Rightarrow v=2.98\times 10^{-2}\times 124.62\\\Rightarrow v=3.71\ \text{m/s}

Tangential speed at the required point is 3.71\ \text{m/s}

Radial acceleration is given by

a=\omega^2r\\\Rightarrow a=124.62^2\times 7.9\times 10^{-2}\\\Rightarrow a=1226.88\approx 1.23\ \text{km/s}^2

The radial acceleration is 1.23\ \text{km/s}^2.

t = Time = 2.06 s

Distance traveled is given by

d=vt\\\Rightarrow d=\omega rt\\\Rightarrow d=124.62\times 7.9\times 10^{-2}\times 2.06\\\Rightarrow d=20.28\ \text{m}

The total distance a point on the rim moves in the required time is 20.28\ \text{m}.

8 0
3 years ago
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Howler monkeys are the loudest land animal on the planet and a single one can be heard from as far as 2.6 km away.
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Answer:

Between 128dB and 149dB

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When howling the Howler monkies has a volume between 128db and 149dB. This is as a result of them having a large hyoid bone in the neck.

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