The velocity of Ned as measured by Pam is the interpretation of v.
Answer: Option D
<u>Explanation:</u>
According to question, we know that this is an issue depending on the logical and translation of the factors. From the measured information taken what is gathered by the two people is communicated and we have given as:
The Ned reference framework : (x, t)
The Pam reference framework :
From the reference framework, we realize that ν is the speed of Pam (the other reference framework) as estimation by Ned.
At that point, is the speed of Ned (from the other arrangement of the reference) as estimation by Pam.
Answer:
a) 27 Joules
b) 27 Joules
c) 1.8m
Explanation:
m = 1.5kg
v = 6m/s
KE = 0.5 * m * v * v
KE = 0.5 * 1.5 * 6 * 6
= 27J
PE = KE = 27J (Kinetic Energy is converted to Potential Energy at the maximum height. This is one of the applications of conservation of energy)
PE = 27 = mgh where g is the acceleration due to gravity of the earth and it has a constant of
solving for h which will be the maximum height the ball reaches, we have
h = 27/(1.5*10)
h = 1.8m
Answer:
(a). H = 8.83 m
(b). Rising
Explanation:
Given,
- Initial velocity of the ball = u = 22.6 m/s
- Height of the crossbar = h = 3.05 m
- Distance of the crossbar from the initial position of the ball = r = 36.0 m
- Angle of projection =
- Initial horizontal velocity of the ball =
- Initial vertical velocity of the ball =
part (a)
In the horizontal direction,
Ball is moving with the constant initial velocity of
Let 't' be the time of the ball to reach at the crossbar of distance r.
At time 't', let 'y' be the vertical displacement attained by the ball.
From the equation of kinematics,
Total distance of the ball above the crossbar = H = y - h = 11.88 - 3.05 = 8.83 m
part (b)
At the maximum height, vertical velocity of the ball becomes zero,
Let h be the maximum height attained by the ball.
From the kinematics,
Maximum height attained by the ball with the given initial velocity is 13.92 m but at the crossbar it attains 11.88 m. Hence the ball will still rising approaching the crossbar.
Answer:
1.785 m/s
Explanation:
The momentum can be calculated using the expression below
M1 *V1 + M2 * V2 = (M1+M2) V3
M1= mass of van=9000 kg
M2= mass of car= 850kg
V3= velocity of entangled car
V1= Velocity of the van= 0
V2= velocity of the car= 5 m/ s
Substitute the values
(900×0) + (500×5)=( 900+500)× V3
2500=1400 V3
V3=2500/1400
V3= 1.785 m/s
Hence, velocity of the entangled cars after collision is 1.785 m/s