Answer:
Steps:
1. Create a text file that contains blade diameter (in feet), wind velocity (in mph) and the approximate electricity generated for the year
2. load the data file for example, in matlab, use ('fileame.txt') to load the file
3. create variables from each column of your data
for example, in matlab,
x=t{1}
y=t{2}
4. plot the wind velocity and electricity generated.
plot(x, y)
5. Label the individual axis and name the graph title.
title('Graph of wind velocity vs approximate electricity generated for the year')
xlabel('wind velocity')
ylabel('approximate electricity generated for the year')
Answer:
Please see the attached file for the complete answer.
Explanation:
Answer:
KAT
Explanation:
I believe this is what ur looking for
Answer:
particles of a solid object packed together
Answer:
(a) 2.39 MPa (b) 3.03 kJ (c) 3.035 kJ
Explanation:
Solution
Recall that:
A 10 gr of air is compressed isentropically
The initial air is at = 27 °C, 110 kPa
After compression air is at = a450 °C
For air, R=287 J/kg.K
cv = 716.5 J/kg.K
y = 1.4
Now,
(a) W efind the pressure on [MPa]
Thus,
T₂/T₁ = (p₂/p₁)^r-1/r
=(450 + 273)/27 + 273) =
=(p₂/110) ^0.4/1.4
p₂ becomes 2390.3 kPa
So, p₂ = 2.39 MPa
(b) For the increase in total internal energy, is given below:
ΔU = mCv (T₂ - T₁)
=(10/100) (716.5) (450 -27)
ΔU =3030 J
ΔU =3.03 kJ
(c) The next step is to find the total work needed in kJ
ΔW = mR ( (T₂ - T₁) / k- 1
(10/100) (287) (450 -27)/1.4 -1
ΔW = 3035 J
Hence, the total work required is = 3.035 kJ
