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Ksenya-84 [330]
3 years ago
8

During glycolysis, for every 6 moles of glucose that enter the pathway, how many moles of atp are used? how many moles atp are g

enerated? how many moles of nadh are used? how many moles of pyruvate are made?
Chemistry
1 answer:
Goryan [66]3 years ago
7 0
During the process of glycolysis 1 mole of glucose yields 2 pyruvic acid. In the process 2 ATPs molecules are used up and 4 other ATP molecules are produced by substrate level phosphorylation and 2 NADH are also produced. Therefore; for six moles of glucose; 12 ATP molecules will be used up, 24 ATP molecules will be generated, 12 moles of NADH will be used and 12 moles of pyruvate are made. 
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If you have 5.42 x 1024 aluminum atoms, approximately how many moles is that
sattari [20]

Answer:

<h2>9.00 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{5.42 \times  {10}^{24} }{6.02 \times {10}^{23} }  \\  = 9.0033

We have the final answer as

<h3>9.00 moles</h3>

Hope this helps you

4 0
3 years ago
Explain why magnesium and aluminium react in a similar way?
postnew [5]
Because magnesium loses its electrons easily than aluminum
3 0
3 years ago
What product(s) forms at the cathode in the electrolysis of an aqueous solution of k2so4?
fenix001 [56]
Catod(-)
K⁺
2H20 +2e⁻ ---> H2 +2OH⁻

We can also say, that
K⁺ +OH⁻ +H2  = KOH +H2   
At the cathode KOH and H2 are formed.
8 0
3 years ago
Balance CH2O + H2 &gt; CH3OH
Tju [1.3M]

Answer:

I believe it is balanced

Explanation:

8 0
3 years ago
30g of naoh is dissolved in 1.5 liter solution the active mass of naoh is?
Pepsi [2]

Answer:

0.5mol/L

Explanation:

First, let us calculate the number of mole NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the question = 30g

Number of mole = Mass /Molar Mass

Number of mole = 30/40 = 0.75mol

Volume = 1.5L

Active mass = mole/Volume

Active mass = 0.75mol/1.5L

Active mass = 0.5mol/L

7 0
3 years ago
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