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Lubov Fominskaja [6]
3 years ago
12

What is the final concentration if 75.0 ml of a 3.50 m glucose solution is diluted to a volume of 400.0 ml?

Chemistry
1 answer:
Eduardwww [97]3 years ago
8 0

Answer:  the final concentration is 0.656M

Explanation:

The <em>concentration</em> may be expressed in several ways. In this case, since the data talks about volume of the <em>solution</em>, the correct unit of the value 3.50 is M (capital M, and not m), so it is <em>3.50 M, which means 3.50 Molar</em>

Hence, we are dealing with molarity.

The equation for molarity, M, is:

  • M = number of moles of solute / volume of solution in liters

Wnen you solve for the number of moles of solute, you get:

  • number of moles of solute = M × volume in liters of the solution

<em>When it is said that the glucose solution is diluted to a volume of 400.0 ml</em>, means than only solvent was added. That implies, that the number of moles of solute of the final (diluted) solution is the same number of moles of the 3.50 M glucose solution.

That permits you to wite theses equations:

  • # moles of glucose in 3.50 M solution, n₁

         n₁ = 3.50 M × 75.0 ml × 1 liter/1000 ml

  • # moles of glucose in the diluted solution, n₂

        n₂ = C × 400.0ml × 1 liter / 1000 ml

  • n₁ = n₂

    ⇒ 3.50 M × 75.0 ml × 1 liter/1000 ml = C × 400.0ml × 1 liter / 1000 ml

  • Solve for the unknown concentration, C:

        C = 3.50 M × 75.0 / 400.0 = 0.656M

The answer is expressed with three significant digits, because 75.0 ml and 3.50 M are expressed with three significant digits.

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