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Airida [17]
3 years ago
7

I need help with the first problem

Chemistry
1 answer:
kati45 [8]3 years ago
8 0

Answer: I would look at this it is reliable

Explanation:

quizletcom/133263618/chapter-15-study-guide-flash-cards/

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What is the density of an 84.7 g sample of an unknown substance if the sample occupies 49.6cm cubed
Ahat [919]

Answer:

             1.70 g.cm⁻³

Solution:

Data Given;

                   Mass  =  84.7 g

                   Volume  =  49.6 cm³

                   Density  =  ?

Formula Used;

                   Density  =  Mass ÷ Volume

Putting values,

                   Density  =  84.7 g ÷ 49.6 cm³ 

                   Density  =  1.70 g.cm⁻³

7 0
3 years ago
if 3.26 g is dissolved in enough water to make exactly 323 ml of solution, what is the molar cocentration of nitrate ion g
AnnyKZ [126]
Divide both sides to get 104 and that’s your answer
5 0
3 years ago
Room temperature is approximately 20°C for scientific purposes. A hot pan on a stove can reach temperatures up to about 260°C. G
DochEvi [55]

The melting points of sugar and salt are above 20°C.

<h3>What is melting point?</h3>

The melting points of substances refer to the temperature at which solid substances gain enough energy to become liquids.

The room temperature is approximately 20°C. At this temperature, sugar and salt are solids. This means that the melting temperature of both substances is above 20°C.

More specifically, sugar will melt around 180 °C while salt will melt at a temperature slightly above 800 °C.

More on melting points can be found here: brainly.com/question/25777663

#SPJ1

4 0
2 years ago
A total of 20.0 mL of sodium hydroxide (NaOH) was neutralized by 30.0 mL of 0.250 M hydrogen bromide (HBr). What was the concent
Karolina [17]

Answer:

0.375 M

Explanation:

NaOH(aq) + HBr(aq) ------------> NaBr(aq) + H2O(l)

Concetration of acid CA= 0.250M

Concentration of base CB= ????

Volume of acid VA= 30.0mL

Volume of base VB= 20.0mL

Number of moles of acid nA= 1

Number of moles of base nB= 1

CA VA/CB VB= nA/nB

CB= CAVAnB/VB nA

= 0.25× 30×1/20×1= 0.375 M

8 0
3 years ago
How many different elements are present in c6h12o6
Margarita [4]

Answer:

3 different elements are present in the compound.

5 0
2 years ago
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