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noname [10]
3 years ago
6

Uranium can be isolated from its ores b6 dissolving it as

Chemistry
2 answers:
ankoles [38]3 years ago
6 0
It’s ores by dissolving it
Ilya [14]3 years ago
5 0

Answer:

Uranium can be isolated from its ores by dissolving it as UO 2(NO3)2, then separating it as solid UO2(C2O4)∙3H2O.

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Which of the following reactions is the least energetic? Question 18 options: ATP + H2O → ADP + Pi ATP + H2O → AMP + PPi AMP + H
Mama L [17]

Answer:

The correct answer is AMP+H2O→ Adenosine + pi

Explanation:

The above reaction is least energetic because there is no phosphoanhydride bond present with adenosine mono phosphate.Phospho anhydride bond is an energy rich bond.

As a result hydrolysis of AMP generates very little amount of energy in comparison to the hydrolysis of ATP and ADP.

   

8 0
3 years ago
Compare the modern (electron cloud) model of the atom with Bohr’s atomic model. Which of these statements describe the two model
AfilCa [17]

Answer:

B. Bohr’s model electrons cannot exist between orbits, but in the electron cloud model, the location of the electrons cannot be predicted.

AND

C. The modern model explains all available data about atoms; Bohr’s model does not.

Explanation:

The answers are right on Edge. :)

6 0
3 years ago
Read 2 more answers
Quickly Please!!!!!!
FrozenT [24]

Answer:

n=4.1mol

Explanation:

Hello,

In this case, we can use the ideal gas equation:

PV=nRT

So we know the temperature, pressure and volume, therefore we can easily compute the required moles as shown below:

n=\frac{PV}{RT}=\frac{2.0atm*101L}{0.082\frac{atm*L}{mol*K}*600K}  \\\\n=4.1mol

Best regards.

5 0
3 years ago
Read 2 more answers
Please answer this Q:
Anarel [89]
D. container four because of the water
3 0
3 years ago
PLEASE HELP & SHOW WORK
Olegator [25]

Answer:

1. 0.178 moles ; 2. 8x10²³ atoms ; 3. 7.22x10²³ molecules ; 4. 89.6 g ; 5. 1.34x10²² atoms ; 6. 1.67x10²⁵ molecules

Explanation:

1. Mass / Molar mass = Mol

5g / 28 g/m = 0.178 moles

2. 1 molecule of N₂ has 2 atoms, it is a dyatomic molecule.

4x10²³  x2 = 8x10²³ atoms

3. 1 mol of anything, has 6.02x10²³ particles

6.02x10²³ molecules . 1.2 mol = 7.22x10²³

4. 1 atom of C weighs 12 amu.

4.5x10²⁴ weigh ( 4.5x10²⁴ . 12) = 5.24x10²⁵ amu

1 amu = 1.66054x10⁻²⁴g

5.24x10²⁵ amu = (5.24x10²⁵ . 1.66054x10⁻²⁴) = 89.6 g

5. Molar mass NaCl = 58.45 g/m

1.3 g /  58.45 g/m = 0.0222 moles

1 mol has 6.02x10²³ atoms

0.0222 moles → ( 0.0222 . 6.02x10²³) = 1.34x10²²

6. Density of water is 1 g/mL, so 500 mL are contained in 500 g of water

Molar mass H₂O = 18 g/m

500 g / 18 g/m = 27.8 moles

6.02x10²³ molecules . 27.8 moles = 1.67x10²⁵

8 0
3 years ago
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