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goblinko [34]
3 years ago
11

Number of atoms in 125 g of C2H22011

Chemistry
1 answer:
USPshnik [31]3 years ago
3 0
Is correct hope this helps i have done this before
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What the volume of 59.2 grams of number 94. The density of plutonium is 19.8 g/cm^ 3
Alex787 [66]

Answer:

C) 2.99 cm^3

Explanation:

ρ=m/V

V=m/ρ=59.2/19.8=2.99 cm^3

5 0
3 years ago
What volume in kiloliters will a sample of Bay water occupy if it has a volume of 125 ml?
Mamont248 [21]
This question is basically asking us to convert the volume from mL to kL.

We can do this by setting up a multiplication problem and cancelling out units:

\frac{125mL}{1}* \frac{1L}{1000mL} * \frac{1kL}{1000L}  =1.25* 10^{-4}kL

So now we know that the Bay water will occupy 1.25x10^-4 kL.
6 0
3 years ago
Read 2 more answers
7. A student has a 25 g sample of gas in a container at STP and adds another 7
BigorU [14]

Answer:

New temperature t2 = [1.28T− 273.15]° C

Explanation:

Given:

Volume v1 = 25 gram

New volume v2 = 25 + 7 = 32 gram

Constant pressure = p

Temperature t1 = T

Find:

New temperature t2

Computation:

Pv1/t1 = Pv2/t2

25 / T = 32 / t2

t2 = 1.28T

New temperature t2 = [1.28T− 273.15]° C

4 0
3 years ago
Which metal can be obtain from calvertie ores?​
galina1969 [7]

Answer:

Ore

hope this helps

thanks for the points

5 0
2 years ago
Which one of the following equations represents the net ionic equation for the reaction between aqueous potassium chloride and a
Nana76 [90]
<h3>Answer:</h3>

Ag⁺(aq) +Cl⁻(aq) → AgCl(s)

<h3>Explanation:</h3>

The questions requires we write the net ionic equation for the reaction between aqueous potassium chloride and aqueous silver nitrate.

<h3>Step 1: Writing a balanced equation for the reaction.</h3>
  • The balanced equation for the reaction between aqueous potassium chloride and aqueous silver nitrate will be given by;

KCl(aq) + AgNO₃(aq) → KNO₃(aq) +AgCl(s)

  • AgCl is the precipitate formed by the reaction.
<h3>Step 2: Write the complete ionic equation.</h3>
  • The complete ionic equation for the reaction is given by showing all the ions involved in the reaction.

K⁺(aq)Cl⁻(aq) + Ag⁺(aq)NO₃⁻(aq) → K⁺(aq)NO₃⁻(aq) +AgCl(s)

  • Only ionic compounds are split into ions.
<h3>Step 3: Write the net ionic equation for the reaction.</h3>
  • The net ionic equation for a reactions only the ions that fully participated in the reaction and omits the ions that did not participate in the reaction.
  • The ions that are not involved directly in the reaction are known as spectator ions and are not included while writing net ionic equation.

Ag⁺(aq) +Cl⁻(aq) → AgCl(s)

4 0
3 years ago
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