Answer: The correct option is 
Explanation:
Atomic mass of calcium ,Ca = 40.07 g/mol
Atomic mass of chlorine ,Cl = 35.5 g/mol
Molar mass of 
:
= (Atomic mass of Ca+2 × (Atomic mass of Cl))
= (40.07 g/mol + (2 × 35.5))=111.07 g/mol
Hence, the correct option is
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Ba(OH)2 + 2 HNO3 -----> Ba(NO3)2 + 2 H2O
1) Calculate moles of Ba(OH)2 used.
0.65 mol / L x 0.0234 L = 0.01521 mol Ba(OH)2
2) Calculate moles of HNO3 used.
0.01521 mol Ba(OH)2 x 2 HNO3 / 1 Ba(OH)2 = 0.03042 mol HNO3
3) Calculate molarity of HNO3.
0.03042 mol / 0.0425 L =
so the answer is 0.716 M !
Answer:
This metal could be lead
Specific heat = 0.0308 cal/g°C
Explanation:
Step 1: Data given
The metal was heated to 115.0°C
in a calorimeter where it cooled to 32.6°C.
Mass of the metal = 25.0 grams
Heat released = 63.5 cal
Step 2: Calculate the specific heat of the metal
Q = m*c*ΔT
⇒with Q = the heat released = 63.5 cal
⇒with m = the mass of the metal = 25.0 grams
⇒with ΔT = the change of temperature = T2 - T1 = 32.6 °C - 115.0°C = -82.4 °C
⇒ c = the specific heat = TO BE DETERMINED
63.5 = 25.0 * c * 82.4
C = 0.0308 cal/g°C
This metal could be lead
Mass of solute = 45.8 g
Mass of solvent = 205 g
solute / ( solute + solvent )
45.8 / ( 45.8 + 205 )
45.8 / 250.8
= 0.182 x 100 = 18.2% by mass
hope this helps!
