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2 years ago

Help me name these molecules please

Chemistry

1 answer:

MrMuchimi2 years ago

6 0

Answer:

1. carboxylic acid

2. ether

3. ester

4. aldehyde

5. ketone

6. amine

7. alcohol

Explanation:

Know the functional groups. If you would like to learn them, let me know.

- Hope that helps! Please let me know if you need further explanation.

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Which compound is classified as a hydrocarbon? A) butanal B) butyne C) 2-butanol D) 2-butanone

fenix001 [56]

Answer:

butyne

Explanation:

alkane, alkene, and alkyne are all examples of hydrocarbons.

butyne = alkyne

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2 years ago

Consider the following equilibrium:

Ainat [17]

<u>Answer: </u>The equation which is wrong is $K_p=K_c(RT)^{-5}$

<u>Explanation:</u>

For the given reaction:

$4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)$

The expression for $K_c\text{ and }K_p$ is given by:

$K_c=\frac{1}{[O_2]^3}$

$K_p=\frac{1}{[O_2]^3}$

The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.

Relationship between $K_p\text{ and }K_c$ is given by the expression:

$K_p=K_c\times (RT)^{\Delta n_g}$

where,

$\Delta n_g$ = number of moles of gaseous products - number of moles of gaseous reactants

R = gas constant

T= temperature

For the above reaction,

$\Delta n_g$ = number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3

Hence, the expression for $K_p$ is:

$K_p=K_c\times (RT)^{-3}$

Therefore, the equation which is wrong is $K_p=K_c(RT)^{-5}$

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3 years ago

Sailin' Steve likes to test the buoyancy of different objects. He threw a spherical object into a fluid that has a greater densi

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The spherical object will float and the square object will sink to the bottom of the fluid as it has greater density. :)

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3 years ago

Two descriptions about physical quantities are given below:

gladu [14]

Answer:

Quantity A is weight and Quantity B is mass

Explanation: weight has same unit as force. Mass is the quantity of matter present in a body or object

8 0

2 years ago

Read 2 more answers

7. How many moles of mercury(ii) oxide, hgo, are needed to produce 12. 5 g of oxygen, o2? 2 hgo(s) --->2 hg(l) o2(g)

svetoff [14.1K]

Moles are the division of the mass and the molar mass. The moles of mercury (ii) oxide in the decomposition reaction needed to produce oxygen are 0.781 moles.

<h3>What is a decomposition reaction?</h3>

A decomposition reaction is a breakdown of the reactant into simpler products. The decomposition of mercury (ii) oxide can be shown as:

2HgO(s) → 2Hg(l) + O₂(g)

From the reaction, it can be said that 2 moles of mercury (ii) oxide decomposes to produce 1 mole of oxygen.

The moles of oxygen that needs to be produced are calculated as:

Moles = mass ÷ molar mass

= 12.5 gm ÷ 32 gm/mol

= 0.39 moles

0.39 moles of oxygen are needed to be produced.

From the stoichiometric coefficient of the reaction, the moles of HgO is calculated as: 2 × 0.39 = 0.781 moles

Therefore, 0.781 moles of HgO are required in the reaction.

Learn more about moles here:

brainly.com/question/3801333

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1 year ago