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MA_775_DIABLO [31]
3 years ago
15

Which coefficients will balance this equation? * Ag + C2 > AC2

Chemistry
1 answer:
SCORPION-xisa [38]3 years ago
7 0

Answer:

16Ag + 2C2 ---> 4 Ag4C

Explanation:

Ag + C2 ----> AgC2

The valence of Ag is one

Valence of Carbon is four

A balanced equation would be

16Ag + 2C2 ---> 4 Ag4C

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Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)
Reptile [31]

<u>Answer:</u> The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]

For the given chemical reaction:

C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]

We are given:

\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

4 0
3 years ago
Explain how the removal of thermal energy (heat) from matter affects its particles
den301095 [7]

Answer:

You can change an object's state of matter by adding or removing thermal energy. When you add thermal energy to an object, these things can happen: Particles move faster

Explanation:

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6 0
3 years ago
What is the total energy change for the following reaction: CO + H2O -&gt; CO2 + H2?
liubo4ka [24]

1)Delta H=(Delta H of reactants)-(Delta H of products)

2)And we know CO have 3 bond CO and CO2 have 2 bond that each of them are 2 bond, please see the picture!

so lets answer it:

(3 \times 358) + (2 \times 463) - (4 \times 358) - 436 = 132

4 0
3 years ago
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