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Yakvenalex [24]
3 years ago
9

A professor of statistics wants to test that the average amount of money a typical college student spends per day during spring

break is over $70. Based upon previous research, the population standard deviation is estimated to be $17.32. The professor surveys 35 students and finds that the mean spending is $72.43. Which of the following statements is most accurate? Select one: a. reject the null hypothesis at ? = 0.01 b. reject the null hypothesis at ? = 0.10 c. fail to reject the null hypothesis at ? ? 0.10 d. reject the null hypothesis at ? = 0.05
Mathematics
1 answer:
STALIN [3.7K]3 years ago
5 0

Answer:

Option c: Fail to reject the null hypothesis at α = 0.10

Step-by-step explanation:

We are given;

Population mean; μ = 70

population standard deviation; σ = 17.32

Sample mean; x¯ = 72.43

Sample size; n = 35

Thus;

Null hypothesis; H0: μ = 70

Alternative hypothesis; Ha: μ > 70

Z-score formula is;

z = (x¯ - μ)/(σ/√n)

z = (72.43 - 70)/(17.32/√35)

z = 2.43/2.9276

z = 0.83

From online p-value from z-score calculator attached, using z = 0.83; significance level = 0.05 and one tailed hypothesis, we have;

P-value ≈ 0.2033

It's more than the significance value, so we will fail to reject the null hypothesis at α = 0.05

Similarly, From online p-value from z-score calculator attached, using z = 0.83; significance level = 0.01 and one tailed hypothesis, we have;

P-value ≈ 0.2033

It's more than the significance value, so we will fail to reject the null hypothesis at α = 0.01

Similarly, From online p-value from z-score calculator attached, using z = 0.83; significance level = 0.10 and one tailed hypothesis, we have;

P-value ≈ 0.2033

It's more than the significance value, so we will fail to reject the null hypothesis at α = 0.10

From the 3 significance values, the correct option is option c. fail to reject the null hypothesis at α = 0.10

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What are you asking?
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3 years ago
Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean number of gallons of gasoline sold to his custom
ira [324]

Answer:

a) The best estimator for the population mean is given by the sample mean \hat \mu = \bar X = 5.70

b) The 99% confidence interval would be given by (4.969;6.431)    

c) We are 99% confident that the true mean for th number of gallons of gasoline  sold to his customers is between 4.969 and 6.431.

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1.9 represent the population standard deviation

n=45 represent the sample size  

2) Part a

The best estimator for the population mean is given by the sample mean \hat \mu = \bar X = 5.70

3) Part b. Develop a 99 percent confidence interval for the population mean.

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

5.7-2.58\frac{1.9}{\sqrt{45}}=4.969    

5.7+2.58\frac{1.9}{\sqrt{45}}=6.431

So on this case the 99% confidence interval would be given by (4.969;6.431)    

4) Part c. Interpret the meaning of part (b).

On this case we can say this: We are 99% confident that the true mean for th number of gallons of gasoline  sold to his customers is between 4.969 and 6.431.

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Answer:

Following are the solution to the given question:

Step-by-step explanation:

Let x_{ij}=1 when i is the element itself is allocated to 'j' i_0

Min  

185X_{1A}+225X_{1B} +193X_{1C} +207X_{1D} +200X_{2A} +190X_{2B} +175X_{2C}+225X_{2D}+330X_{3A} +320X_{3B} +315X_{3C}+300X_{3D}+375X_{4A}+389X_{4B}+425X_{4C}+ 445X_{4D}

Subject to:

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the answer is false

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