Answer:
Weight = 3.924 N
Bouyant force = 2.5N
Apperent weight= 1.424N
Explanation:
Radius of the sphere = 0.0165 m
Volume of sphere = (4πr³)/3
Volume = 4.189*(4.49*10^-6)
Volume = 1.88*10^-5
For the weight.
Mass = density* volume
Mass = 2.14*10^4 *(1.88*10^5)
Mass = 0.4 kg.
Weight = mass * acceleration due to gravity
Weight = 0.4*9.81
Weight = 3.924 N
For the buoyant force Fb
Fb = volume * density of fluid* acceleration
Fb = (1.88*10^5)*1.36 × 10^ 4*9.81
Fb = 2.5N
For Apperent weight
True weight - buoyant force = Apperent weight.
3.924- 2.5N= 1.424N
Answer:
Their experimental design lacks control group
Explanation:
Based on what I read, the scientists don't have a control group as one of the main groups thus they cannot, in scientific sense, say that the medicine is better or worse. You always need a control group receiving no intervention because then we can compare groups and assess the effectiveness of that intervention (in our case if we had control group vs people who received the medicine, we could see if the people who received the medicine had improved condition etc when compared to participants who did not receive anything)
Option(a) the mass of cart 2 is twice that of the mass of cart 1 is the right answer.
The mass of cart 2 is twice that of the mass of cart 1 is correct about the mass of cart 2.
Let's demonstrate the issue using variables:
Let,
m1=mass of cart 1
m2=mass of cart 2
v1 = velocity of cart 1 before collision
v2 = velocity of cart 2 before collision
v' = velocity of the carts after collision
Using the conservation of momentum for perfectly inelastic collisions:
m1v1 + m2v2 = (m1 + m2)v'
v2 = 0 because it is stationary
v' = 1/3*v1
m1v1 = (m1+m2)(1/3)(v1)
m1 = 1/3*m1 + 1/3*m2
1/3*m2 = m1 - 1/3*m1
1/3*m2 = 2/3*m1
m2 = 2m1
From this we can conclude that the mass of cart 2 is twice that of the mass of cart 1.
To learn more about inelastic collision visit:
brainly.com/question/14521843
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Work is defined as the force times the distance which is mathematically expressed W = Fxd. The given force is 5x10^4 and the distance is 10000 m (the distance is converted as meter because Nm = J) the work done by the wind is W = 5x10^4 N (10000) = 500 x 10^6 Joules. I hope it answered your question
Answer:
L = 3.35 m
Explanation:
given,
mass of the block = 0.2 Kg
spring constant = 1.40 kN/m
until spring compressed = 10 cm
inclination of ramp = 60°
now,
initial potential energy of spring = (work done by friction) + (final gravitational potential energy of block)
L = 3.35 m