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HACTEHA [7]
3 years ago
15

What is water's density at 93 ∘C? Assume a constant coefficient of volume expansion. Express your answer with the appropriate un

its.
Chemistry
1 answer:
Ganezh [65]3 years ago
3 0

Answer:

982.5 kg/m³

Explanation:

When the temperature of a fluid increases, it dilates, and because of the variation of the volume, it's density will vary too. The density can be calculated by the expression:

ρ₁ = ρ₀/(1 + β*(t₁ - t₀))

Where ρ₁ is the final density, ρ₀ the initial density, β is the constant coefficient of volume expansion, t₁ the final temperature, and t₀ the initial temperature.

At t₀ = 4°C, the water desity is ρ₀ = 1,000 kg/m³. The value of the constant for water is β = 0.0002 m³/m³ °C, so, for t₁ = 93°C

ρ₁ = 1,000/(1 + 0.0002*(93 - 4))

ρ₁ = 1,000/(1+ 0.0178)

ρ₁ = 982.5 kg/m³

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How many moles are 1.20 x 1025 formula units of calcium iodide?
madam [21]

Answer:

19.9 mol

Explanation:

Use <em>Avogadro’s number</em> to convert formula units of CaI₂ to moles of CaI₂.

1 mol CaI₂ ≡ 6.022 × 10²³ formula units CaI₂

Moles of CaI₂ = 1.20 × 10²⁵ × (1 /6.022 × 10²³)

Moles of CaI₂ = 19.9 mol

6 0
3 years ago
3) If an electrical appliance has 150.0 V applied causing a current of 2.34 amps, what is the
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Answer:

The resistance would be 64.10 ohms.

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5 0
3 years ago
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3 0
3 years ago
A lead atom has a mass of 3.14 x 10 to the negative 22nd g.How
frozen [14]

Explanation:

The given data is as follows.

       Mass of a lead atom = 3.14 \times 10^{-22}

       Volume = 2.00 cm^{3}

        Density = 11.3 g/cm^{3}

As it is mentioned that 1 cubic centimeter contains 11.3 grams of lead.

So, in 2 cubic centimeter there will be 2 \times 11.3 g = 22.6 g of lead atoms.

One lead atom has a mass of 3.14 \times 10^{-22}. Therefore, number of atoms present in 22.6 g of lead will be as follows.

                \frac{22.6 g}{3.14 \times 10^{-22}}

                  = 7.197 \times 10^{22} atoms

Thus, we can conclude that there are 7.197 \times 10^{22} atoms of lead are present.

4 0
3 years ago
Acetanilide has a solubility of 1.00 g/185 ml in 25 oc water and 1.00 g/20 ml in 100 oc water. what is the minimum volume of wat
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In the crystallization process the solid compound is dissolved in the solvent at elevated temperature and the crystallize product obtained by slow cooling of the  solution. Here the solubility of acetanilide at 100°C is 1g per 20mL of water. Thus to dissolve 500mg of acetanilide at high temperature that is 100°C we need 10mL of water.

Now at 25°C after the re-crystallization there will be some amount of dissolve acetanilide. Which can be calculated as- 185mL of water is needed to dissolve 1g or 1000mg of acetanilide at 25°C. Thus in 10mL of water there will be \frac{10X1000}{185}=54.05gmg of acetanilide.    

6 0
3 years ago
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