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3 years ago

It is lab investigations day! What clothes should you wear to school?

Chemistry

2 answers:

dusya [7]3 years ago

6 0

Baggy shirt and pants

faust18 [17]3 years ago

6 0

I think either baggy or short. Is this a question or are you just decide if what to wear.

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Chemistry test bound theories

liq [111]

covalent bond is firmed between two atoms

5 0

3 years ago

What is the ratio of [a–]/[ha] at ph 3.75? the pka of formic acid (methanoic acid, h–cooh) is 3.75?

Vikentia [17]

The formula for pH given the pKa and the concentrations are:

pH = pKa + log [a–]/[ha]

<span>
Therefore calculating:</span>

3.75 = 3.75 + log [a–]/[ha]

log [a–]/[ha] = 0

[a–]/[ha] = 10^0

3 0

3 years ago

Read 2 more answers

Describe the reaction below by listing the

rjkz [21]

Answer:

The covalent bond in Cl₂ is break and combine with sodium to form NaCl through ionic bond.

Explanation:

Chemical equation:

Na + Cl₂ → NaCl

Balanced chemical equation:

2Na + Cl₂ → 2NaCl

The given reaction indicate the formation of sodium chloride.

Sodium chloride is an ionic compound. It is formed by the reaction of chlorine and sodium. The type of bond in Cl₂ is covalent. Both chlorine atoms are tightly held together through sharing of electrons. When sodium chloride is formed the covalent between the chlorine atoms are break and it react with sodium . The chlorine toms thus gain the one electron from the sodium atom and became negative ion while sodium by losing its one valance electrons became positive ions. The strong electrostatic forces are develop between them and ionic bond is formed.

6 0

3 years ago

One mole of copper(ii) sulfate, cuso4, contains ________ o atoms.

Ierofanga [76]

According to avogadro constant, the number of units in one mole of any substance contain 6.022 x10 ^23 atoms

therefore the number of o atoms in one mole of CuSO4 = 6.022 x 10 ^ 23

6 0

3 years ago

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How many kilograms of solvent would contain 0.43 mol of CaO in a 2.5 molality solution

dalvyx [7]

<h3>Answer:</h3>

0.024 kg CaO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Aqueous Solutions</u>

Molarity = moles of solute / liters of solution

<u>Atomic Structure</u>

Reading a Periodic Tables
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.41 mol CaO

2.5 M Solution

<u>Step 2: Identify Conversions</u>

1000 g = 1 kg

Molar Mass of Ca - 40.08 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CaO - 40.08 + 16.00 = 56.08 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 0.43 \ mol \ CaO(\frac{56.08 \ g \ Cao}{1 \ mol \ CaO})(\frac{1 \ kg \ CaO}{1000 \ g \ CaO})$
Multiply: $\displaystyle 0.024114 \ kg \ CaO$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

0.024114 kg CaO ≈ 0.024 kg CaO

4 0

3 years ago

Read 2 more answers