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3 years ago

Unless otherwise stated, all objects are located near the Earth's surface, where g = 9.80 m/s2 .

Physics

1 answer:

Andreas93 [3]3 years ago

4 0

Answer:

1) 1.5 m/s^2

2) 4.5 N

Explanation:

From Newton's Second Law of motion, we know

$F=m*a$

Which states that to calculate the force acting on an object, you multiply its mass and acceleration.

So, we know an object of mass 1.5 kg has an acceleration of 3 m/s^2, then

$F=m*a=1.5*3=4.5$

A force of 4.5 N is acting on the object.

If a force of 4.5 N acts on a mass of 3kg we have

$a=\frac{F}{m}=\frac{4.5}{3}=1.5$

So, it would give it an acceleration of 1.5 m/s^2.

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Which of the following best describes the difference between speed and acceleration?

Nataly_w [17]

The correct answer to the question is : C) Speed is the distance an object travels within a specific unit of time, whereas acceleration is the rate at which the speed or direction of an object is changing.

EXPLANATION :

Before going to answer this question, first we have to understand speed and acceleration.

The speed of a body is defined as the rate of change of distance or the distance covered by the body per unit time. Speed is scalar quantity. Hence, it needs only magnitude for its complete specification.

The acceleration produced by a body is defined as the rate of change of velocity. We know that velocity is the speed in a particular direction. Hence, the acceleration is not only produced due to the change in magnitude of velocity as well as due to the change in direction. Hence, acceleration is a vector quantity which needs magnitude as well as direction for its complete specification.

Hence, the best difference between speed and acceleration is the third statement.

3 0

3 years ago

Read 2 more answers

Un hamster esta sentado sobre un tocadisco cuya rapidez angular es constante si el hamster se mueve a un punto localizado al dob

kotegsom [21]

Answer:

b) se duplica

Explanation:

The disk is moving with constant angular velocity, let's call it $\omega$ .

The linear velocity of a point on the disk is given by

$v=\omega r$

where r is the distance of the point from the axis of rotation.

In this problem, the object is moved at a distance twice as far as the initial point, so

$r' = 2r$

Therefore, the new linear velocity is

$v'=\omega r' = \omega (2r) = 2 \omega r = 2 v$

So, the velocity has doubled, and the correct answer is

b) se duplica

8 0

3 years ago

If the radius of an object in circular motion is doubled, what change will occur in the centripetal force?

cestrela7 [59]

Answer:

The centripetal force will be 1/2 as big as it was. (option c)

Explanation:

Recall that centripetal force ( $F_c$ ) is defined as: $F_c=m\,* \frac{v^2}{r}$ where "v" is the tangential velocity of the object in circular motion, "r" is the radius of rotation and "m" is the object's mass.

So if we start with such formula with a given mass, radius, and tangential velocity, and then we move to a situation where everything stays the same except for the radius which doubles, then the new centripetal force ( $F'_c$ ) will be given by: $F'_c=m\,* \frac{v^2}{2r}$