Answer:
Energy density will be 14.73
Explanation:
We have given capacitance
Potential difference between the plates = 365 V
Plate separation d = 0.200 mm
We know that there is relation between electric field and potential
, here E is electric field, V is potential and d is separation between the plates
So
Energy density is given by
Answer:
Fnet=ma
24-13=3a
11/3=a
a=3.6m/s2
Answer:
f = q
Explanation:
In the attachment we can see a diagram of the parallel rays.
The dotted line represents the normal to the mirror surface
These rays when reflected using the constructor equation
where p and q are the distance to the object and the image respectively.
Since the rays are parallel P = inf
1 / f = 1 / inf + 1 / q
f = q
this means that all the rays focus on one focal point.
