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Rudiy27
3 years ago
10

Se trata 50 g de aluminio que posee 10% de impurezas con suficiente cantidad de ácido sulfúrico ¿qué peso de sulfato de aluminio

se obtiene si el porcentaje de rendimiento fue de 70%? P.A. (uma): Al: 27, S = 32, O = 16
Chemistry
1 answer:
Bogdan [553]3 years ago
4 0

Respuesta:

199.5 g

Explicación:

Paso 1: Escribir la reacción balanceada

2 Al + 3 H₂SO₄ ⇒ Al₂(SO₄)₃ + 3 H₂

Paso 2: Calcular la masa pura de 50 g  de Al

Aluminio tiene 10% de impurezas, es decir, 10% de 50 g = 5 g. Luego, tiene 50 g - 5 g = 45 g de Al puro.

Paso 3: Calcular la masa teórica de Al₂(SO₄)₃ obtenida a partir de 45 g de Al

La relación de masas de Al₂(SO₄)₃ a Al es 342:54.

45 g Al × 342 g Al₂(SO₄)₃/54 g Al = 285 g Al₂(SO₄)₃

Paso 4: Calcular la masa real de Al₂(SO₄)₃ obtenida

El rendimiento de la reacción es de 70%.

285 g × 70% = 199.5 g

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