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telo118 [61]
3 years ago
12

Which transition metals have more in common than other

Physics
2 answers:
jeka943 years ago
8 0

Answer:

A. alkali metals

Explanation:

im not sure about that

sukhopar [10]3 years ago
7 0

Answer:

c

Explanation:

haha signs d d Sd Didi d do f idi

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Draw the symbol for the following components.
balu736 [363]

Answer:

Hello dear how are you

Explanation:

Can you will be my friend

And plz always keep smile on your face dear

4 0
3 years ago
Read 2 more answers
The diffuser in a jet engine is designed to decrease the kinetic energy of the air entering the engine compressor without any wo
Mice21 [21]

Answer:

The exit velocity air is 77.56 m/s.

Explanation:

Specific heat of air at 60°C is about 1.006 KJ/kg-K (from standard table).

Now from first law for open system

h_1+\dfrac{V_1^2}{2}+Q=h_2+\dfrac{V_2^2}{2}+w

For ideal gas h=CT

Given that T_1=30°C

T_2=90°C

V_1=356 m/s

By putting the values

1.006\times (273+30)+\dfrac{356^2}{2000}=1.006\times (273+90)+\dfrac{V_2^2}{2000}+

V_2=77.56 m/s

So the exit velocity air is 77.56 m/s.

6 0
3 years ago
Please help with number 2
Norma-Jean [14]

Number 2 is Classify

Hope this helps!

5 0
3 years ago
A 2.00 kg cat is in a 97.00 kg elevator. What force on the elevator cable would be needed to lower the cat/elevator pair with an
umka21 [38]

The magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair is 198 Newton.

<u>Given the following data:</u>

  • Mass of cat = 2 kg
  • Mass of elevator = 97 kg
  • Acceleration = 2 m/s^2

To determine the magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair, we would apply Newton's Second Law of Motion:

First of all, we would calculate the total mass of the cat/elevator pair.

Total \;mass=2 + 97

Total mass = 99 kilograms

Mathematically, Newton's Second Law of Motion is given by this formula;

Force = mass \times acceleration

Substituting the given parameters into the formula, we have;

Force = 99 \times 2

Net force = 198 Newton

Read more here: brainly.com/question/24029674

3 0
3 years ago
A racing car reaches a speed of 42 m/s. It then begins a uniform negative acceleration, using its parachute and braking system,
NARA [144]

As per the question the initial speed of the car [ u] is 42 m/s.

The car applied its brake and comes to rest after 5.5 second.

The final velocity [v] of the car will be zero.

From the equation of kinematics we know that

                                         v=u+at [ here a stands for acceleration]

                                         0=42 +5.5a

                                         a =\frac{-42}{5.5} m/s^2

                                          a= -7.64 m/s^2

Here a is taken negative as it the car is decelerating uniformly.

We are asked to calculate the stopping distance .

From equation of kinematics we know that

                                              S=ut+\frac{1}{2} at^2  [here S is the distance]

                                                      = 42*5.5 +\frac{1}{2} [-7.64] [5.5]^2 m

                                                       =115.445 m      [ans]  

8 0
3 years ago
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