Answer:
The tension force in the supporting cables is 7245N
Explanation:
There are two forces acting on the elevator: the force of gravity pointing down (+) with magnitude (elevator mass) x (gravitational acceleration), and the tension force of the cable pointing up (-) with an unknown magnitude F. The net force is the sum of these forces:
![F_{net} = F_g - F = m\cdot g - F\\](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20F_g%20-%20F%20%3D%20m%5Ccdot%20g%20-%20F%5C%5C)
We are given the resulting acceleration along with the mass, i.e., we know the net force, allowing us to solve for F:
![1150kg\cdot 3.5\frac{m}{s^2}= 1150kg \cdot 9.8\frac{m}{s^2}-F\\\implies F = 1150kg\cdot(9.8-3.5)\frac{m}{s^2}= 7245N](https://tex.z-dn.net/?f=1150kg%5Ccdot%203.5%5Cfrac%7Bm%7D%7Bs%5E2%7D%3D%201150kg%20%5Ccdot%209.8%5Cfrac%7Bm%7D%7Bs%5E2%7D-F%5C%5C%5Cimplies%20F%20%3D%201150kg%5Ccdot%289.8-3.5%29%5Cfrac%7Bm%7D%7Bs%5E2%7D%3D%207245N)
The tension force F in the supporting cables is 7245N
When a magnet is dropped, the domain become unaligned.
Answer:
speed of puck acc. to the radar gun = 138 km/h
speed of player = 15 km/h
since the player is in motion when he shoots, the speed of the puck will be the sum of the speed of the player and the speed at which he shot. so,
speed of puck = speed of player + speed of puck acc. to player
138 = 15 + speed of puck acc. to player
speed of puck acc. to player = 138 -15
speed of puck acc. to player = 123 km/h
Brainly this answer if you think it deserves it
Answer:
The object will travel at a constant rate in along a straight line.
Explanation:
In the given situation, it is mentioned that there is no external force acting on the given object. Thus, it will retain its initial velocity along a straight path.
Answer:
<em>Hydrogen bond is the attractive force between the hydrogen attached electronegative atom </em>
Explanation: