Answer:
Hello dear how are you
Explanation:
Can you will be my friend
And plz always keep smile on your face dear
Answer:
The exit velocity air is 77.56 m/s.
Explanation:
Specific heat of air at 60°C is about 1.006 KJ/kg-K (from standard table).
Now from first law for open system

For ideal gas h=CT
Given that
°C
°C

By putting the values


So the exit velocity air is 77.56 m/s.
The magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair is 198 Newton.
<u>Given the following data:</u>
- Acceleration = 2

To determine the magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair, we would apply Newton's Second Law of Motion:
First of all, we would calculate the total mass of the cat/elevator pair.

Total mass = 99 kilograms
Mathematically, Newton's Second Law of Motion is given by this formula;

Substituting the given parameters into the formula, we have;

Net force = 198 Newton
Read more here: brainly.com/question/24029674
As per the question the initial speed of the car [ u] is 42 m/s.
The car applied its brake and comes to rest after 5.5 second.
The final velocity [v] of the car will be zero.
From the equation of kinematics we know that
[ here a stands for acceleration]



Here a is taken negative as it the car is decelerating uniformly.
We are asked to calculate the stopping distance .
From equation of kinematics we know that
[here S is the distance]
![= 42*5.5 +\frac{1}{2} [-7.64] [5.5]^2 m](https://tex.z-dn.net/?f=%3D%2042%2A5.5%20%2B%5Cfrac%7B1%7D%7B2%7D%20%5B-7.64%5D%20%5B5.5%5D%5E2%20m)
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