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telo118 [61]
3 years ago
12

Which transition metals have more in common than other

Physics
2 answers:
jeka943 years ago
8 0

Answer:

A. alkali metals

Explanation:

im not sure about that

sukhopar [10]3 years ago
7 0

Answer:

c

Explanation:

haha signs d d Sd Didi d do f idi

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Red Riding Hood sat down to rest and placed her 1.20-kg basket of goodies beside her. A wolf came along, spotted the basket, and
anygoal [31]

Answer:

  117.6°

Explanation:

The vertical component of a force directed at some angle α from the vertical is ...

  F·cos(α)

We want the vertical components of the wolf's force (Fw) and Red's force (Fr) to total zero. So for some angle from vertical α, Red's force will satisfy ...

  Fw·cos(25°) + Fr·cos(α) = 0

  cos(α) = -Fw/Fr·cos(25°) ≈ -(6.4 N)/(12.5 N)·0.906308 ≈ -0.464030

  α ≈ arccos(-0.464030) ≈ 117.6°

Red was pulling at an angle of about 117.6° from the vertical.

_____

<em>Additional comment</em>

That's about 27.6° below the horizontal.

3 0
2 years ago
All of the planets and their satellites orbit the Sun in the same direction, and all their orbits lie near the same plane. True
MissTica

Answer:

True

Explanation:

The Sun rotates in the counterclockwise (CCW) direction when seen from its north pole. Since, the planets revolve around the Sun because of its gravity, the revolution of all the planets and their moons as seen from the north of the Sun is in CCW direction.

In fact most of the solar system bodies rotate in the same direction that is CCW. Some major exceptions to this are Venus and Uranus.

Almost all the planets and moons were made from the planetary disk around the Sun. Thus, they lie nearly in the same plane.

4 0
2 years ago
In a playground, there is a small merry-go-round of radius 1.20 m and mass 160 kg. Its radius of gyration is 91.0 cm. (Radius of
aksik [14]

Answer:

a) 145.6kgm^2

b) 158.4kg-m^2/s

c) 0.76rads/s

Explanation:

Complete qestion: a) the rotational inertia of the merry-go-round about its axis of rotation 

(b) the magnitude of the angular momentum of the child, while running, about the axis of rotation of the merry-go-round and

(c) the angular speed of the merry-go-round and child after the child has jumped on.

a) From I = MK^2

I = (160Kg)(0.91m)^2

I = 145.6kgm^2

b) The magnitude of the angular momentum is given by:

L= r × p The raduis and momentum are perpendicular.

L = r × mc

L = (1.20m)(44.0kg)(3.0m/s)

L = 158.4kg-m^2/s

c) The total moment of inertia comprises of the merry- go - round and the child. the angular speed is given by:

L = Iw

158.4kgm^2/s = [145kgm^2 + ( 44.0kg)(1.20)^2]

w = 158.6/208.96

w = 0.76rad/s

7 0
3 years ago
How do you find the water pressure at the bottom of the 55-m-high water tower?
svp [43]
-- What's the volume of a cylinder with radius=1m and height=55m ?

         ( Volume of a cylinder = π R² h )

-- How much does that volume of water weigh ?

            1 liter of water = 1 kilogram of mass
            Weight = (mass) x (acceleration of gravity) 

-- What's the area of the bottom of that 1m-radius cylinder ?

       Pressure  =  (force) / (area)
5 0
3 years ago
1. 1500j of work was done to move a box 20m. What force was applied to the box ?
Fantom [35]

Answer:

1. 75N

2. 67,983 J (=67.98 kJ)

Explanation:

1. Work = Force x Distance

we are given that Work = 1,500J and Distance = 20m

hence,

Work = Force x Distance

1,500 = Force x 20

Force = 1,500 ÷ 20 = 75N

2. Potential Energy, PE = mass x gravity x change in height

we are given that mass = 165 kg and change in height = 42m

assuming that gravity, g = 9.81 m/s²

Potential Energy, PE = mass x gravity x change in height

Potential Energy, PE = 165 x 9.81 x 42 = 67,983 J (=67.98 kJ)

4 0
3 years ago
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