If 1.08 g of sodium sulfate reacts with an excess of phosphoric acid, how much sulfuric acid is produced?
1 answer:
Answer: 0.745 g of will be produced from 1.08 g of sodium sulfate
Explanation:
To calculate the moles :
is the limiting reagent as it limits the formation of product and is the excess reagent.
According to stoichiometry :
3 moles of produce = 3 moles of
Thus 0.0076 moles of will require= of
Mass of
Thus 0.745 g of will be produced from 1.08 g of sodium sulfate
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