Answer:
Resistance is inversely proportional to current, so when the resistance doubles, the current is cut in half. Resistance is directly proportional to current, so when the resistance doubles, the current is cut in half.
Divide
(the distance covered in some period of time)
by
(the time taken to cover the distance).
The quotient is the average speed during that period of time.
Hear is transferred from the heating elements to the Pot by Conductivity
Answer:

Explanation:
<u>Coulomb's Law</u>
The force between two charged particles of charges q1 and q2 separated by a distance d is given by the Coulomb's Law formula:

Where:

q1, q2 = the objects' charge
d= The distance between the objects
We know both charges are identical, i.e. q1=q2=q. This reduces the formula to:

Since we know the force F=1 N and the distance d=1 m, let's find the common charge of the spheres solving for q:

Substituting values:


This charge corresponds to a number of electrons given by the elementary charge of the electron:

Thus, the charge of any of the spheres is:

