"A toy airplane flies clockwise at a constant speed in a horizontal circle of radius 8.0 meters. The magnitude of the accelerati
on of the airplane is 25 meters per second squared. The diagram shows the path of the airplane as it travels around the circle.
Calculate the speed of the airplane. [Show all work, including the equation and substitution with units.]"
Calculate the speed of the airplane. [Show all work, including the equation and substitution with units.]"
2 answers:
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Answer:
C)the right cord pulls on the pulley with greater force than the left cord
Explanation:
As we can see the figure that B is connected to the right string while A is connected to the left string
Now force equation for B as it will move downwards is given as
similarly for block A which will move upwards we can write the equation as
now we know that pulley is also rotating so the tangential acceleration of the rope at the contact point with pulley must be same as that of acceleration of the blocks
so here pulley will rotate clockwise direction
So tension in the right string must be more than the left string
So correct answer will be
C)the right cord pulls on the pulley with greater force than the left cord
The momentum of the object is 8050 kg m/s
Explanation:
The momentum of an object is defined as
where
p is the momentum
m is the mass
v is the velocity of the object
For the object in this problem, we have
m = 500 kg is its mass
v = 58 km/h is its velocity
Converting the velocity into m/s,
Therefore now we can find the momentum of the object:
Learn more about momentum:
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The intensity of the magnetic force F experienced by a charge q moving with speed v in a magnetic field of intensity B is equal to
where
is the angle between the directions of v and B.
1) Re-arranging the previous formula, we can calculate the value of the magnetic field intensity. The charge is
. In this case, v and B are perpendicular, so 
, therefore we have:
2) In this second case, the angle between v and B is
. The charge is now 
, and the magnetic field is the one we found in the previous part, B=2.8 T, so we can find the intensity of the force experienced by this second charge:
where
1) Re-arranging the previous formula, we can calculate the value of the magnetic field intensity. The charge is
2) In this second case, the angle between v and B is