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Juliette [100K]
3 years ago
14

Please help me currently failing junior year

Chemistry
2 answers:
saveliy_v [14]3 years ago
5 0
b hope it’s right !!
MrRa [10]3 years ago
4 0

Answer:

option B

hope this helps :D

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A study of the decomposition reaction 3RS2  3R + 6S yields the following initial rate dat
shutvik [7]
Missing question: What is the rate constant for the reaction?
<span>[RS2](mol L-1) Rate (mol/(L·s))
0.150                0.0394
0.250                0.109
0.350                0.214
0.500                0.438</span>
Chemical reaction: 3RS₂ → 3R + 6S.
Compare second and fourth experiment, when concentration is doubled, rate of concentration is increaced by four. So rate is:
rate = k·[RS₂]².
k = 0,438 ÷ (0,500)².
k = 1,75 L/mol·s.
3 0
3 years ago
Water is composed of one atom of oxygen and two atoms of
egoroff_w [7]

Answer:

<em>Hydrogen.</em>

Explanation:

You've probably seen "H_{2}0" which is the formula for water. It means that there's 2 hydrogen atoms, and one oxygen atom, in one molecule of water.

<em>Hope this helps! Feel free to mark me Brainliest if you feel this helped. :)</em>

3 0
3 years ago
Read 2 more answers
What can you infer from the fact that nitrogen gas is useless to animals?
makvit [3.9K]

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Denitrification changes nitrogen into a gaseous form.

Explanation:

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8 0
3 years ago
The balanced redox reactions for the sequential reduction of vanadium are given below.
Minchanka [31]

Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.

Explanation :

Let us rewrite the given equations again.

2VO_{2}^{+} (aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2VO^{2+}(aq)+Zn^{2+}+2H2O(l)2VO^{2+}(aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2V^{3+} (aq)+Zn^{2+}+2H2O(l)

2V^{3+} (aq)+ Zn (s)\rightarrow 2V^{2+}(aq)+Zn^{2+}(aq)

On adding above equations, we get the following combined equation.

2VO_{2}^{+} (aq)+ 8H^{+} (aq) + 3Zn (s)\rightarrow 2V^{2+}(aq)+3Zn^{2+}(aq)+4H_{2}O(l)

We have 12.1 mL of 0.033 M solution of VO₂⁺.

Let us find the moles of VO₂⁺ from this information.

12.1 mL \times \frac{1L}{1000mL}\times \frac{0.033mol}{L}=0.0003993mol NO_{2}^{+}

From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.

Let us use this as a conversion factor to find the moles of Zn.

0.0003993mol NO_{2}^{+}\times \frac{3mol Zn}{2molNO_{2}^{+}}=0.00059895mol Zn

Let us convert the moles of Zn to grams of Zn using molar mass of Zn.

Molar mass of Zn is 65.38 g/mol.

0.00059895mol Zn\times \frac{65.38gZn}{1molZn}=0.0392gZn

We need 0.0392 grams of Zn metal to completely reduce vanadium.

6 0
3 years ago
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