Answer
given,
L(t) = 10 - 3.5 t
mass of particle = 2 Kg
radius of the circle = 3.1 m
a) torque
τ = 
τ = 
τ = -3.5 N.m
Particle rotates clockwise as i look down the plane. Hence, its angular velocity is downward.
L decreases the angular acceleration upward. so, net torque is upward.
b) Moment of inertia of the particle
I = m R^2
I = 2 x 3.1²
I = 19.22 kg.m²
L = I ω
ω = 
ω = 
ω = 
A = 0.52 rad/s B = -0.182 rad/s²
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Top left: slowing down
Top right: not moving
Bottom left: moving at a constant speed
Bottom right: speeding up
Answer:
4
Explanation:
From the question given above, the following data were obtained:
Effort (E) = 80 lbs
Load (L) = 320 lbs
Mechanical advantage (MA) =?
Mechanical advantage is simply defined as the ratio of load to effort. Mathematically, it is expressed as:
Mechanical advantage = Load / Effort
MA = L / E
With the above formula, we can obtain the mechanical advantage as illustrated below:
Effort (E) = 80 lbs
Load (L) = 320 lbs
Mechanical advantage (MA) =?
MA = L / E
MA = 320 / 80
MA = 4
Thus, the mechanical advantage is 4