The energy conservation and trigonometry we can find the results for the questions about the movement of the acrobat are;
a) The maximum speed is v = 4.89 m / s
b) The maximum height is h = 1.22 m
The energy conservation is one of the most fundamental principles of physics, stable that if there are no friction forces the mechanistic energy remains constant. Mechanical energy is the sum of the kinetic energy plus the potential energies.
Em = K + U
Let's write the energy in two points.
Starting point. Highest part of the oscillation
Em₀ = U = m g h
Final point. Lower part of the movement
= K = ½ m v²
Energy is conserved.
Emo =
m g h = ½ m v²
v² = 2 gh
Let's use trigonometry to find the height, see attached.
h = L - L cos θ
h = L (1- cos θ)
They indicate that the initial angle is tea = 48º and the length is L = 3.7 m, let's calculate.
h = 3.7 (1- cos 48)
h = 1.22 m
this is the maximum height of the movement.
Let's calculate the velocity.
v = 4.89 m / s
In conclusion using the conservation of energy and trigonometry we can find the results for the questions about the movement of the acrobat are;
a) The maximum speed is v = 4.89 m / s
b) The maximum height is h = 1.22 m
Learn more here: brainly.com/question/13010190
Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
P.E. = 5880
Kinetic Energy (Final One) = 1/2 mv²
K.E. = 1/2 * 60 * (10)²
K.E. = 6000/2
K.E. = 3000
Lost Energy = 5880 - 3000 = 2880 J
In short, Your Answer would be 2880 Joules
Hope this helps!
Answer:
The tension in the rope is 262.88 N
Explanation:
Given:
Weight
N
Length of rope
m
Initial speed of ball 
For finding the tension in the rope,
First find the mass of rod,
(
)

kg
Tension in the rope is,


N
Therefore, the tension in the rope is 262.88 N
Answer:
The energy which is produced by a battery is 101.1 kJ.
Explanation:
The expression for the energy in terms of voltage, current and time is as follows;
E=VIt
Here, V is the voltage, I is the current and t is the time.
It is given in the problem that a battery can provide a current of 1.80 A at 2.60 V for 6.00 hr.
Calculate the energy of the battery.
E=VIt
Convert time from hour int seconds.
t=6 hr
t=(6)(60)(60)
t=21600 s
Put I= 1.80 A, V= 2.60 V and t= 21600 s in the expression of energy.
E=(2.60)(1.80)(21600)
E= 101.1 kJ
Therefore, the energy which is produced by a battery is 101.1 kJ.