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Mariulka [41]
3 years ago
6

find the upward force in Newton when each of these is under water(density of 1g/cm3) a lump of iron of volume 2000cm3​

Physics
1 answer:
shutvik [7]3 years ago
5 0

Answer:

Upthrust = 19.6 N

Explanation:

When an object is immersed under water, the upward force it experience is called an upthrust. An upthrust is a force which is applied on any object in a fluid which acts in an opposite direction to the direction of the weight of the object.

Upthrust = density of liquid x gravitational force x volume of object

i.e U = ρ x g x vol

Given: ρ = 1g/cm^{3} (1000 kg/m^{3}), volume = 2000 cm^{3} (0.002 m^{3}) and g = 9.8 m/s^{2}

So that;

U = 1000 x 9.8 x 0.002 (kg/m^{3} x m^{3} x m/s^{2})

   = 19.6 Kg m/s^{2}

U = 19.6 Newtons

The upthrust on the iron is 19.6 N.

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The average lifetime of a poodle dog is 13.0 years. How fast is it traveling, u, relative to an observer who measures the averag
bogdanovich [222]

Answer:

The speed is 0.97 c.

Explanation:

Given that,

Dilated time t'= 50.0 years

Rest time t = 13.0 years

We need to calculate the speed

Using formula of time dilation

t'=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}}}

Where, t' = change in time

t = rest time

v = velocity

c = speed of light

Put the value into the formula

50.0=\dfrac{13.0}{\sqrt{1-\dfrac{v^2}{(3\times10^{8})^2}}}

v^2=\dfrac{(13)^2\times(c)^2-(c)^2\times50^2}{50^2}

v^2= 0.9324c^2

v=0.97c

Hence, The speed is 0.97 c.

6 0
3 years ago
Interestingly, there have been several studies using cadavers to determine the moment of inertia of human body parts by letting
loris [4]

Answer:

0.08735 kgm²

Explanation:

m = Mass of lower leg = 5 kg

L = Length of leg = 18 cm

g = Acceleration due to gravity = 9.81 m/s²

f = Frequency = 1.6 Hz

I = Moment of inertia

Time period is given by

T=2\pi\sqrt{\dfrac{I}{mgL}}

Also

T=\dfrac{1}{f}

So,

I=\dfrac{mgL}{(2\pi f)^2}\\\Rightarrow I=\dfrac{5\times 9.81\times 0.18}{(2\pi 1.6)^2}\\\Rightarrow I=0.08735\ kgm^2

The moment of inertia of the lower leg is 0.08735 kgm²

8 0
4 years ago
A 21.3 A current flows in a long, straight wire. Find the strength of the resulting magnetic field at a distance of 45.7 cm from
Bezzdna [24]

Answer:

The magnetic field strength due to current flowing in the wire is9.322 x 10⁻⁶ T.

Explanation:

Given;

electric current, I = 21.3 A

distance of the magnetic field from the wire, R = 45.7 cm = 0.457 m

The strength of the resulting magnetic field at the given distance is calculated as;

B = \frac{\mu_o I}{2\pi R}

Where;

μ₀ is permeability of free space = 4π x 10⁻⁷ T.m/A

B = \frac{\mu_o I}{2\pi R}\\\\B = \frac{4\pi*10^{-7} *21.3}{2\pi(0.457)}\\\\B = 9.322 *10^{-6} \ T

Therefore, the magnetic field strength due to current flowing in the wire is 9.322 x 10⁻⁶ T.

7 0
3 years ago
In a 35 mm single lens reflex camera (SLR) the distance from the lens to the film is varied in order to focus on objects at vary
Evgesh-ka [11]

Answer:

range of movement is 1.49 mm

Explanation:

given data

focal length = 45 mm

distance = 1.4 m

distance from the lens = 35 mm

distance from infinity down = 1.4 m =

to find out

range of movement

solution

we will apply here lens equation that is

1/f = 1/p + 1/q

here f = 45 and p =  infinity to 1400 mm

we find here image distance that is q

1/45 = 0 + 1/q             ......1

q = 45 mm

and

1/45 = 1/1400 + 1/q     ......2

q = 46.49

so range of movement

that is 46.49 - 45

range of movement is 1.49 mm

8 0
3 years ago
Chapter 05, Problem 15 Multiple-Concept Example 7 and Concept Simulation 5.2 review the concepts that play a role in this proble
Llana [10]

Answer:

Explanation:

The question relates to motion on a circular path .

Let the radius of the circular path be R .

The centripetal force for circular motion is provided by frictional force

frictional force is equal to μmg , where μ is coefficient of friction and mg is weight

Equating cenrtipetal force and frictionl force in the case of car A

mv² / R = μmg

R = v² /μg

= 26.8 x 26.8 / .335 x 9.8

= 218.77 m

In case of moton of car B

mv² / R = μmg

v²  = μRg

= .683  x 218.77x 9.8

= 1464.35

v = 38.26 m /s .

3 0
3 years ago
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