Answer:
The speed is 0.97 c.
Explanation:
Given that,
Dilated time t'= 50.0 years
Rest time t = 13.0 years
We need to calculate the speed
Using formula of time dilation

Where, t' = change in time
t = rest time
v = velocity
c = speed of light
Put the value into the formula




Hence, The speed is 0.97 c.
Answer:
0.08735 kgm²
Explanation:
m = Mass of lower leg = 5 kg
L = Length of leg = 18 cm
g = Acceleration due to gravity = 9.81 m/s²
f = Frequency = 1.6 Hz
I = Moment of inertia
Time period is given by

Also

So,

The moment of inertia of the lower leg is 0.08735 kgm²
Answer:
The magnetic field strength due to current flowing in the wire is9.322 x 10⁻⁶ T.
Explanation:
Given;
electric current, I = 21.3 A
distance of the magnetic field from the wire, R = 45.7 cm = 0.457 m
The strength of the resulting magnetic field at the given distance is calculated as;

Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ T.m/A

Therefore, the magnetic field strength due to current flowing in the wire is 9.322 x 10⁻⁶ T.
Answer:
range of movement is 1.49 mm
Explanation:
given data
focal length = 45 mm
distance = 1.4 m
distance from the lens = 35 mm
distance from infinity down = 1.4 m =
to find out
range of movement
solution
we will apply here lens equation that is
1/f = 1/p + 1/q
here f = 45 and p = infinity to 1400 mm
we find here image distance that is q
1/45 = 0 + 1/q ......1
q = 45 mm
and
1/45 = 1/1400 + 1/q ......2
q = 46.49
so range of movement
that is 46.49 - 45
range of movement is 1.49 mm
Answer:
Explanation:
The question relates to motion on a circular path .
Let the radius of the circular path be R .
The centripetal force for circular motion is provided by frictional force
frictional force is equal to μmg , where μ is coefficient of friction and mg is weight
Equating cenrtipetal force and frictionl force in the case of car A
mv² / R = μmg
R = v² /μg
= 26.8 x 26.8 / .335 x 9.8
= 218.77 m
In case of moton of car B
mv² / R = μmg
v² = μRg
= .683 x 218.77x 9.8
= 1464.35
v = 38.26 m /s .